我想知道是否有可能创建一个Java java.util.List,它只允许添加元素但不允许删除元素?Java list only only addition删除
我正在考虑重写删除方法的一种方法。请建议。
我想知道是否有可能创建一个Java java.util.List,它只允许添加元素但不允许删除元素?Java list only only addition删除
我正在考虑重写删除方法的一种方法。请建议。
这可以使用Decorator模式来实现。这样,它可以适用于实现List
所有容器:
private static class UnremovableList<E> implements List<E> {
private List<E> innerContainer;
public UnremovableList(List<E> original) {
innerContainer = original
}
@Override
public void add(int location, E object) {
innerContainer.add(location, object);
}
@Override
public boolean add(E object) {
return innerContainer.add(object);
}
@Override
public boolean addAll(int location, Collection<? extends E> collection) {
return innerContainer.addAll(location, collection);
}
@Override
public boolean addAll(Collection<? extends E> collection) {
return innerContainer.addAll(collection);
} -
@Override
public void clear() {
throw new UnsupportedOperationException();
}
@Override
public boolean contains(Object object) {
return innerContainer.contains(object);
}
@Override
public boolean containsAll(Collection<?> collection) {
return innerContainer.containsAll(collection);
}
@Override
public E get(int location) {
return innerContainer.get(location);
}
@Override
public int indexOf(Object object) {
return innerContainer.indexOf(object);
}
@Override
public boolean isEmpty() {
return innerContainer.isEmpty();
}
@NonNull
@Override
public ListIterator<E> listIterator() {
return listIterator(0);
}
@NonNull
@Override
public Iterator<E> iterator() {
return new Iterator<E>() {
Iterator<E> iterator = innerContainer.iterator();
@Override public boolean hasNext() {
return iterator.hasNext();
}
@Override public E next() {
return iterator.next();
}
@Override public void remove() {
throw new UnsupportedOperationException();
}
};
}
@Override
public ListIterator<E> listIterator(final int location) {
return new ListIterator<E>() {
ListIterator<E> iterator = innerContainer.listIterator(location);
@Override public void add(E object) {
throw new UnsupportedOperationException();
}
@Override public boolean hasNext() {
return iterator.hasNext();
}
@Override public boolean hasPrevious() {
return iterator.hasPrevious();
}
@Override public E next() {
return iterator.next();
}
@Override public int nextIndex() {
return iterator.nextIndex();
}
@Override public E previous() {
return iterator.previous();
}
@Override public int previousIndex() {
return iterator.previousIndex();
}
@Override public void remove() {
throw new UnsupportedOperationException();
}
@Override public void set(E object) {
throw new UnsupportedOperationException();
}
};
}
@Override
public int lastIndexOf(Object object) {
return innerContainer.lastIndexOf(object);
}
@Override
public E remove(int location) {
throw new UnsupportedOperationException();
}
@Override
public boolean remove(Object object) {
throw new UnsupportedOperationException();
}
@Override
public boolean removeAll(Collection<?> collection) {
throw new UnsupportedOperationException();
}
@Override
public boolean retainAll(Collection<?> collection) {
throw new UnsupportedOperationException();
}
@Override
public E set(int location, E object) {
return innerContainer.set(location, object);
}
@Override
public int size() {
return innerContainer.size();
}
@NonNull
@Override
public List<E> subList(int start, int end) {
return new UnremovableList(innerContainer.subList(start, end));
}
@NonNull
@Override
public Object[] toArray() {
return innerContainer.toArray();
}
@NonNull
@Override
public <T> T[] toArray(T[] array) {
return innerContainer.toArray(array);
}
}
用法:
List<String> stableList = new UnremovableList(Arrays.asList("A", "B", "C"));
有利于构图而不是继承,以及支持迭代器的奖励点。但是'subList()'可能需要类似的处理。 –
@JiriTousek谢谢。我用'UnremovableList'封装了原始'subList()' - 现在它应该可以工作 – j2ko
可以扩展现有列表实现类并覆盖所有公共删除方法,但是它有相当多的方法来重写(甚至更多,下面都是我很快就找到)
public class UnDeletableList<E> extends ArrayList<E> {
@Override
public E remove(int index) {
throw new UnsupportedOperationException("don't remove from this list");
}
@Override
public boolean remove(Object o) {
throw new UnsupportedOperationException("don't remove from this list");
}
@Override
public boolean removeAll(Collection<?> o) {
throw new UnsupportedOperationException("don't remove from this list");
}
@Override
public boolean retainAll(Collection<?> o) {
throw new UnsupportedOperationException("don't remove from this list");
}
@Override
public void clear() {
throw new UnsupportedOperationException("don't remove from this list");
}
// OPTIONAL IN CASE OF EXTRA STRICTNESS
@Override
public void replaceAll(UnaryOperator<E> u) {
throw new UnsupportedOperationException("don't remove from this list");
}
@Override
public E set(int i, E e) {
throw new UnsupportedOperationException("don't remove from this list");
}
}
为什么要停止使用删除一个程序员的所有的努力?或者,如果您正在实现继承List接口的自定义对象,则只需将remove重写为一个不做任何事情的函数。在创建一个不同的List对象停止删除的麻烦似乎没有必要? –
最简单的方法是对现有的List实现中的一个子类进行子类化并覆盖remove方法。 –
同意覆盖列表类,但没有做任何事我会建议引发异常,所以用户知道他们做错了什么 –