d3.js力布局增加linkDistance

Question

如何增加linkDistance不影响节点定位，

例如：http://mbostock.github.com/d3/talk/20110921/force.html

当我尝试增加圆半径和linkDistance 了它崩溃

<script type="text/javascript"> 

var w = 1280, 
    h = 800, 
    z = d3.scale.category20c(); 

var force = d3.layout.force() 
    .size([w, h]); 

var svg = d3.select("#chart").append("svg:svg") 
    .attr("width", w) 
    .attr("height", h); 

svg.append("svg:rect") 
    .attr("width", w) 
    .attr("height", h); 

d3.json("flare.json", function(root) { 
    var nodes = flatten(root), 
     links = d3.layout.tree().links(nodes); 

    force 
     .nodes(nodes) 
     .links(links) 
     .start(); 

    var link = svg.selectAll("line") 
     .data(links) 
    .enter().insert("svg:line") 
     .style("stroke", "#999") 
     .style("stroke-width", "1px"); 

    var node = svg.selectAll("circle.node") 
     .data(nodes) 
    .enter().append("svg:circle") 
     .attr("r", 4.5) 
     .style("fill", function(d) { return z(d.parent && d.parent.name); }) 
     .style("stroke", "#000") 
     .call(force.drag); 

    force.on("tick", function(e) { 
    link.attr("x1", function(d) { return d.source.x; }) 
     .attr("y1", function(d) { return d.source.y; }) 
     .attr("x2", function(d) { return d.target.x; }) 
     .attr("y2", function(d) { return d.target.y; }); 

    node.attr("cx", function(d) { return d.x; }) 
     .attr("cy", function(d) { return d.y; }); 
    }); 
}); 

function flatten(root) { 
    var nodes = []; 
    function recurse(node, depth) { 
    if (node.children) { 
     node.children.forEach(function(child) { 
     child.parent = node; 
     recurse(child, depth + 1); 
     }); 
    } 
    node.depth = depth; 
    nodes.push(node); 
    } 
    recurse(root, 1); 
    return nodes; 
} 

    </script> 

Answer 1

玩弄.charge parameter。它定义了多少节点相互排斥。