SFML rendertexture不返回纹理

我有一个问题得到sfml rendertexture正确地返回它的纹理我相信我已经缩小到这一点的代码。我相信这与我试图将rendertexture中的纹理复制到纹理贴图的方式有关。SFML rendertexture不返回纹理

renderedchunks将是私人我只是公开测试功能快速。

这里的头文件

#ifndef TILE_MAP_H 
#define TILE_MAP_H 
#include "SFML/Graphics.hpp" 
#include <map> 
#include "Chunk.h" 
//Class designed to manipulate chunks 
// 


class Tile_Map 
{ 
public: 
    Tile_Map(); 
    void RenderChunk(Texture_Manager&, int x, int y); 
    void CreateChunk(int x, int y); //Eventually will create based on biomes 
    std::map<int, std::map<int, sf::Texture> > renderedchunks; 



protected: 
private: 



    std::map<int, std::map<int, Chunk> > chunkmap; //Used to store all created chunks 



};

这里的cpp文件

#include "Tile_Map.h" 

Tile_Map::Tile_Map() 
{ 
//ctor 
} 

void Tile_Map::CreateChunk(int x, int y) 
{ 

chunkmap[x][y]; 
Chunk& chunk = chunkmap[x][y]; 
chunk.SetBiome("grass"); 
} 

void Tile_Map::RenderChunk(Texture_Manager& tempmanager, int x, int y) 
{ 
sf::RectangleShape drawable[8][8]; 
sf::RenderTexture drawingtexture; 
Chunk& rchunk = chunkmap[x][y]; 

float renderx = 0; 
float rendery = 0; 

if(rchunk.GetBiome() == "grass") 
{ 
    for(int it = 0; it < 8; it++) 
    { 
     for(int it2 = 0; it2 < 8; it2++) 
     { 
      drawable[it][it2].setTexture(&tempmanager.GetTexture("grass")); 
      drawable[it][it2].setPosition(renderx, rendery); 
      drawingtexture.draw(drawable[it][it2]); 
      std::cout << "x = " << renderx << std::endl; 
      renderx += 32; 

     } 
     renderx = 0; 
     std::cout << "y = " << rendery << std::endl; 
     rendery += 32; 
    } 
} 
drawingtexture.display(); 
renderedchunks[x][y] = drawingtexture.getTexture(); 

}

来源

2015-10-19 Joshua