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我正在使用NSRegularExpression读取文本并找出hashtag。 这是我在regularExpressionWithPattern中使用的NSString。NSRegularExpression ISSUE
- (NSString *)hashtagRegex
{
return @"#((?:[A-Za-z0-9-_]*))";
//return @"#{1}([A-Za-z0-9-_]{2,})";
}
这是我的方法:
// Handle Twitter Hashtags
detector = [NSRegularExpression regularExpressionWithPattern:[self hashtagRegex] options:0 error:&error];
links = [detector matchesInString:theText options:0 range:NSMakeRange(0, theText.length)];
current = [NSMutableArray arrayWithArray:links];
NSString *hashtagURL = @"http://twitter.com/search?q=%23";
//hashtagURL = [hashtagURL stringByAddingPercentEscapesUsingEncoding:NSASCIIStringEncoding];
for (int i = 0; i < [links count]; i++) {
NSTextCheckingResult *cr = [current objectAtIndex:i];
NSString *url = [theText substringWithRange:cr.range];
NSString *nohashURL = [url stringByReplacingOccurrencesOfString:@"#" withString:@""];
nohashURL = [nohashURL stringByReplacingOccurrencesOfString:@" " withString:@""];
[theText replaceOccurrencesOfString:url
withString:[NSString stringWithFormat:@"<a href=\"%@%@\">%@</a>", hashtagURL, nohashURL, url]
options:NSLiteralSearch
range:NSMakeRange(0, theText.length)];
current = [NSMutableArray arrayWithArray:[detector matchesInString:theText options:0 range:NSMakeRange(0, theText.length)]];
}
[theText replaceOccurrencesOfString:@"\n" withString:@"<br />" options:NSLiteralSearch range:NSMakeRange(0, theText.length)];
[_aWebView loadHTMLString:[self embedHTMLWithFontName:[self fontName]
size:[self fontSize]
text:theText]
baseURL:nil];
一切工作,但它想出了一个小问题,当我使用这样的字符串:
NSString * theText = @"#twitter #twitterapp #twittertag";
我的代码只凸显#twitter在每个单词上,而不是它的第二部分(#twitter #twitter(app)#twitter(tag))。 我希望有人能帮助我!
谢谢:)
魅力!! –