MySQL查询帮助

Question

我有以下5个表：

users(user_id) 
books(book_id, author_id) 
source_phrases(source_phrase_id, book_id, phrase) 
synonym_phrases(synonym_phrase_id, source_phrase_id, reader_id, synonym) 
synonym_ratings(synonym_ratings_id, synonym_phrase_id, rater_id, rating) 

我想获得一个查询，将选择一个用户已完成审查的所有书籍。

的用户将完成审查一本书，如果他们所做每个源短语如下：

用户已经提示了资源短语的同义词（reader_id在synonym_phrases表是用户ID）

OR

用户已经额定源短语的同义词（在synonym_ratings表rater_id是用户ID）

我花了一整天试图与无欢得到这个。任何帮助将非常感激。

Answer 1

SELECT b.* 
FROM books b 
WHERE book_id NOT IN 
     (
     SELECT sp.book_id 
     FROM source_phrases sp 
     WHERE source_phrase_id NOT IN 
       (
       SELECT syp.source_phrase_id 
       FROM synonym_phrases syp 
       WHERE reader_id = @user_id 
       ) 
       AND source_phrase_id NOT IN 
       (
       SELECT syp.source_phrase_id 
       FROM synonym_phrases syp 
       JOIN synonym_ratings sr 
       ON  sr.synonym_phrase_id = syp.synonym_phrase_id 
         AND sr.rater_id = @user_id 
       ) 
     ) 
     AND book_id IN 
     (
     SELECT sp.book_id 
     FROM source_phrases sp 
     )