DATEDIFF

Question

我使用datediff得到两个日期时间之间的差异四舍五入到最接近的30分钟：此

DATEDIFF(hh, CAST(CAST(dbo.QuickLabDump.[Date Entered] AS DATE) AS DATETIME) 
    + CAST(dbo.QuickLabDump.[Time Entered] AS TIME), 
    CAST(CAST(dbo.QuickLabDump.[Date Completed] AS DATE) AS DATETIME) 
    + CAST(dbo.QuickLabDump.[Time Completed] AS TIME)) AS [Hours TurnAround] 

我不明白，我从这句话得到的行为，但我需要的是什么，是>= :30, round up, if not, round down,

问题如何在30分钟内完成下舍入，如果大于或等于30分钟，可以将小时数累加起来？

Answer 1

您应该计算在几分钟内DATEDIFF，做一个ROUND则：

ROUND(CAST(DATEDIFF(MINUTES, CAST(CAST(dbo.QuickLabDump.[Date Entered] AS DATE) AS DATETIME) 
         + CAST(dbo.QuickLabDump.[Time Entered] AS TIME), CAST(CAST(dbo.QuickLabDump.[Date Completed] AS DATE) AS DATETIME) 
         + CAST(dbo.QuickLabDump.[Time Completed] AS TIME)) AS FLOAT)/60,0) AS [Hours TurnAround]