以毫秒为户头，而使用_DateDiff（）

Question

我想在Excel中，计算2个细胞之间经过的时间，通过以下的AutoIt方法：

_DateDiff ($sType, $sStartDate, $sEndDate) 

我的问题是，这个功能不会在几毫秒到帐户。 它以秒为单位给我经过的时间，但我希望它在秒+毫秒。

有没有人知道如何获得两个单元之间的时间间隔，包括毫秒与AutoIt？

谢谢:)

Answer 1

1. 你可以扩展自己的功能。

2. 你可以计算出你的数值* 1000和之后的功能/ 1000。

   ; #FUNCTION# ==================================================================================================================== 
   ; Author ........: Jos van der Zande 
   ; Modified.......: 
   ; =============================================================================================================================== 
   Func _DateDiff($sType, $sStartDate, $sEndDate) 
       ; Verify that $sType is Valid 
       $sType = StringLeft($sType, 1) 
       If StringInStr("d,m,y,w,h,n,s", $sType) = 0 Or $sType = "" Then 
        Return SetError(1, 0, 0) 
       EndIf 
       ; Verify If StartDate is valid 
       If Not _DateIsValid($sStartDate) Then 
        Return SetError(2, 0, 0) 
       EndIf 
       ; Verify If EndDate is valid 
       If Not _DateIsValid($sEndDate) Then 
        Return SetError(3, 0, 0) 
       EndIf 
       Local $asStartDatePart[4], $asStartTimePart[4], $asEndDatePart[4], $asEndTimePart[4] 
       ; split the StartDate and Time into arrays 
       _DateTimeSplit($sStartDate, $asStartDatePart, $asStartTimePart) 
       ; split the End Date and time into arrays 
       _DateTimeSplit($sEndDate, $asEndDatePart, $asEndTimePart) 
       ; ==================================================== 
       ; Get the differens in days between the 2 dates 
       Local $aDaysDiff = _DateToDayValue($asEndDatePart[1], $asEndDatePart[2], $asEndDatePart[3]) - _DateToDayValue($asStartDatePart[1], $asStartDatePart[2], $asStartDatePart[3]) 
       ; ==================================================== 
       Local $iTimeDiff, $iYearDiff, $iStartTimeInSecs, $iEndTimeInSecs 
       ; Get the differens in Seconds between the 2 times when specified 
       If $asStartTimePart[0] > 1 And $asEndTimePart[0] > 1 Then 
        $iStartTimeInSecs = $asStartTimePart[1] * 3600 + $asStartTimePart[2] * 60 + $asStartTimePart[3] 
        $iEndTimeInSecs = $asEndTimePart[1] * 3600 + $asEndTimePart[2] * 60 + $asEndTimePart[3] 
        $iTimeDiff = $iEndTimeInSecs - $iStartTimeInSecs 
        If $iTimeDiff < 0 Then 
         $aDaysDiff = $aDaysDiff - 1 
         $iTimeDiff = $iTimeDiff + 24 * 60 * 60 
        EndIf 
       Else 
        $iTimeDiff = 0 
       EndIf 
       Select 
        Case $sType = "d" 
         Return $aDaysDiff 
        Case $sType = "m" 
         $iYearDiff = $asEndDatePart[1] - $asStartDatePart[1] 
         Local $iMonthDiff = $asEndDatePart[2] - $asStartDatePart[2] + $iYearDiff * 12 
         If $asEndDatePart[3] < $asStartDatePart[3] Then $iMonthDiff = $iMonthDiff - 1 
         $iStartTimeInSecs = $asStartTimePart[1] * 3600 + $asStartTimePart[2] * 60 + $asStartTimePart[3] 
         $iEndTimeInSecs = $asEndTimePart[1] * 3600 + $asEndTimePart[2] * 60 + $asEndTimePart[3] 
         $iTimeDiff = $iEndTimeInSecs - $iStartTimeInSecs 
         If $asEndDatePart[3] = $asStartDatePart[3] And $iTimeDiff < 0 Then $iMonthDiff = $iMonthDiff - 1 
         Return $iMonthDiff 
        Case $sType = "y" 
         $iYearDiff = $asEndDatePart[1] - $asStartDatePart[1] 
         If $asEndDatePart[2] < $asStartDatePart[2] Then $iYearDiff = $iYearDiff - 1 
         If $asEndDatePart[2] = $asStartDatePart[2] And $asEndDatePart[3] < $asStartDatePart[3] Then $iYearDiff = $iYearDiff - 1 
         $iStartTimeInSecs = $asStartTimePart[1] * 3600 + $asStartTimePart[2] * 60 + $asStartTimePart[3] 
         $iEndTimeInSecs = $asEndTimePart[1] * 3600 + $asEndTimePart[2] * 60 + $asEndTimePart[3] 
         $iTimeDiff = $iEndTimeInSecs - $iStartTimeInSecs 
         If $asEndDatePart[2] = $asStartDatePart[2] And $asEndDatePart[3] = $asStartDatePart[3] And $iTimeDiff < 0 Then $iYearDiff = $iYearDiff - 1 
         Return $iYearDiff 
        Case $sType = "w" 
         Return Int($aDaysDiff/7) 
        Case $sType = "h" 
         Return $aDaysDiff * 24 + Int($iTimeDiff/3600) 
        Case $sType = "n" 
         Return $aDaysDiff * 24 * 60 + Int($iTimeDiff/60) 
        Case $sType = "s" 
         Return $aDaysDiff * 24 * 60 * 60 + $iTimeDiff 
       EndSelect 
   EndFunc ;==>_DateDiff