我正在使用一个Widget,它将获取当前GPS位置并将此值传递给远程PHP页面以获取信息并将其显示在Widget中。这是我想要做的。在android appwidget中实现位置监听器时出现问题
我在为appWidget实现Location Listener时遇到问题。它不是用当前位置进行更新,而是显示最初的小部件,即“加载小部件”(这里我把这个文本)
我们可以为AppWidgetProvider实现位置监听器吗?
或
你能否建议我在App Widget中获取GPS位置的可能解决方案?
我把所有必要的权限放在清单文件中。
这里是我的代码片段:
public class test extends AppWidgetProvider {
static LocationManager locMan;
static Location curLocation;
static Boolean locationChanged;
@Override
public void onUpdate(Context context, AppWidgetManager appWidgetManager,int[] appWidgetIds) {
// To prevent any ANR timeouts, we perform the update in a service
context.startService(new Intent(context, UpdateService.class));
}
public static class UpdateService extends Service {
// GPS Listener Class
LocationListener gpsListener = new LocationListener() {
public void onLocationChanged(Location location) {
// Log.w("GPS", "Started");
if (curLocation == null) {
curLocation = location;
locationChanged = true;
}
if (curLocation.getLatitude() == location.getLatitude() && curLocation.getLongitude() == location.getLongitude())
locationChanged = false;
else
locationChanged = true;
curLocation = location;
if (locationChanged)
locMan.removeUpdates(gpsListener);
}
public void onProviderDisabled(String provider) {
}
public void onProviderEnabled(String provider) {
// Log.w("GPS", "Location changed", null);
}
public void onStatusChanged(String provider, int status,
Bundle extras) {
if (status == 0)// UnAvailable
{
} else if (status == 1)// Trying to Connect
{
} else if (status == 2) {// Available
}
}
};
// In service start method, I am registering for GPS Updates
@Override
public void onStart(Intent intent, int startId) {
locMan = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
if (locMan.isProviderEnabled(LocationManager.GPS_PROVIDER)) {
locMan.requestLocationUpdates(LocationManager.GPS_PROVIDER,20000, 1, gpsListener);
} else {
this.startActivity(new Intent("android.provider.Settings.ACTION_LOCATION_SOURCE_SETTINGS"));
}
if (curLocation != null) {
double lat = curLocation.getLatitude();
double lng = curLocation.getLongitude();
Toast.makeText(getBaseContext(),"Lat : " + String.valueOf(lat) + "\n Long : "+ String.valueOf(lng), Toast.LENGTH_LONG).show();
}
// Build the widget update for today
RemoteViews updateViews = buildUpdate(this);
// Push update for this widget to the home screen
ComponentName thisWidget = new ComponentName(this,InKakinadaWidget.class);
AppWidgetManager manager = AppWidgetManager.getInstance(this);
manager.updateAppWidget(thisWidget, updateViews);
}
public RemoteViews buildUpdate(Context context) {
// Here I am updating the remoteview
return updateViews;
}
@Override
public IBinder onBind(Intent intent) {
// We don't need to bind to this service
return null;
}
}
}
在此先感谢...
与问候, Raghavendra K.
嗨迈克, 我在我的HTC英雄测试。但没有运气。我的代码有问题吗? 还是你可以建议我任何其他方式来获得gps位置的Widget? 感谢您的快速反应... – Raghu 2009-11-26 11:27:32
我很乐意提供帮助,但我对小部件不是很熟悉。我忘记提及的一件事就是确保你使用设备在外面走动 - 过去我一直在努力处理代码,只是意识到设备无法在室内获得GPS定位,因此不会发送给我GPS更新。 – emmby 2009-11-26 17:22:21