2012-10-02 70 views
1
["api",["API","Apiales","Apiaceae","Apicomplexa lifecycle stages","Apia","Apicomplexa","Apidae","APIA Leichhardt Tigers","Apical consonant","Apical membrane"]] 

我该如何解析这个JSON与SBJson解析器的iOS。我需要它,只有这些值的数组:我如何解析这个JSON数据?

"API","Apiales","Apiaceae","Apicomplexa lifecyclestages","Apia","Apicomplexa","Apidae","APIA Leichhardt Tigers","Apical consonant","Apical membrane" 

我当前的代码:

SBJsonParser *parser = [[SBJsonParser alloc] init]; 

// Prepare URL request to download statuses from Twitter 
NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:@"http://en.wikipedia.org/w/api.php?action=opensearch&search=dj&limit=100&namespace=0&format=json"]]; 

// Perform request and get JSON back as a NSData object 
NSData *response = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil]; 

// Get JSON as a NSString from NSData response 
NSString *json_string = [[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding]; 

NSDictionary *results = [json_string JSONValue]; 

NSArray *statuses = [parser objectWithString:json_string error:nil]; 
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你需要支持的iOS版本低于5.0年长?如果不是的话,你应该考虑使用iOS 5中添加的JSON支持。在那之前我使用了SBJsonParser,这很好,但是如果我可以避免的话,我更喜欢避免依赖第三方库。 – Snips

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是的,我需要使用SBJsonParser支持4.1等。我可以找到很多示例代码,但不是如何解析我的类型的json – user1713954

回答

1

尝试,

NSArray *results = [json_string JSONValue]; 

NSArray *statuses = [results objectAtIndex:1]; 
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Works。非常感谢你! – user1713954