1
helou,我有我的函数回调问题。我试图得到一个很好的效果隐藏和showint网站上的内容... 但隐藏和显示功能并没有等待对方,他们自己立即调用自己而不是等待对方完成,我不知道什么即时通讯做错了。jQuery,函数回调即时,不等待
点击Section 1按钮时,子菜单出现在左侧,内容在右侧。当我点击另一个按钮,当前内容应该删除,新的内容必须出现......这是发生..但一切都在同一时间,我不能让他们在队列
<script>
$(document).ready(function() {
$("#sectionOneButton").click(function() {
$(".subSection").hide("drop");
$(".subMenu").hide("drop", function() {
$("#divSubMenu_1").show("slide", { direction: "up" }, function() {
$("#divSubSection_1").show("slide", { direction: "left" });
});
});
});
$("#sectionTwoButton").click(function() {
$(".subSection").hide("drop");
$(".subMenu").hide("drop", function() {
$("#divSubMenu_2").show("slide", { direction: "up" }, function() {
$("#divSubSection_2").show("slide", { direction: "left" });
});
});
});
});
</script>
</head>
<body>
<div id="divWrapper" name="divWrapper" >
<div id="divBanner" name="divBanner" >
</div>
<div id="divNavigation" name="divNavigation">
<button id="homeButton" class="buttonNavigation">Home</button>
<button id="sectionOneButton" class="buttonNavigation">Seccion 1</button>
<button id="sectionTwoButton" class="buttonNavigation">Seccion 2</button>
<button id="sectionThreeButton" class="buttonNavigation">Seccion 3</button>
</div>
<div id="divContent" name="divContent" >
<div id="divSubMenu_1" class="subMenu">
<button class="buttonSubMenu">SubContenido 1</button>
<button class="buttonSubMenu">SubContenido 2</button>
<button class="buttonSubMenu">SubContenido 3</button>
</div>
<div id="divSubMenu_2" class="subMenu">
<button class="buttonSubMenu">SubContenido 4</button>
<button class="buttonSubMenu">SubContenido 5</button>
<button class="buttonSubMenu">SubContenido 6</button>
</div>
<div id="divSubSection_1" class="subSection">
Sub Seccion 1
<input type="text" name="date" id="date" />
</div>
<div id="divSubSection_2" class="subSection">
Sub Seccion 2
<input type="text" name="date" id="date" />
</div>
</div>
<div id="divFooter" name="divFooter" >
</div>
</div>
</body>
</html>
u能为您的代码的jsfiddle? – iJade