如果有多个条件else语句

Question

什么，我试图做我的SQL查询之前设置正确的变量。这是我创建的if语句，但我无法正确回显。下面提供的设置应该回显出fnm，但是会回显nm。我在做什么错误这里有两个变量匹配每个if语句，所以我可以插入正确的数据

$type = "No Notification"; 
$remote = "Yes"; 
if ($type == "No Notification" && $remote == "No"){ 
$type = "nm"; 
} 
elseif ($type == "Email Notification" && $remote == "No"){ 
$type = "m"; 
} 
elseif ($type == "No Notifcation" && $remote == "Yes"){ 
$type = "fnm"; 
} 
elseif ($type == "Email Notification" && $remote == "Yes"){ 
$type = "fm"; 
} 
else { 
$type = "nm"; 
} 

echo $type; 

Answer 1

你的第二个ELSEIF有一个错字：Notifcation应该通知 这些事情发生:)