嗨,我有以下数据。在R中匹配特殊字符
shopping_list <- c("apples x4", "bag of flour", "bag of sugar", "milk x2",
"appple+20gfree",
"BELI HG MSWAT ALA +VAT T 100g BAR WR",
"TOOLAIT CASSE+LSST+SSSRE 40g SAC MDC")
在我的第二步中,我删除了shopping_list
中的所有空格。
require(stringr)
shopping_list_trim <- str_replace_all(shopping_list, fixed(" "), "")
print(shopping_list_trim)
[1] "applesx4" "bagofflour" "bagofsugar"
[4] "milkx2" "appple+20gfree" "BELIHGMSWATALA+VATT100gBARWR"
[7] "TOOLAITCASSE+LSST+SSSRE40gSACMDC"
如果我想提取不包含加号的字符串,我使用下面的代码。
str_extract(shopping_list_trim, "^[^+]+$")
[1] "applesx4" "bagofflour" "bagofsugar" "milkx2" NA NA NA
想帮助提取包含加号的字符串。 我想输出是以下一个。
NA NA NA NA "appple+20gfree"
"BELIHGMSWATALA+VATT100gBARWR" "TOOLAITCASSE+LSST+SSSRE40gSACMDC"
有没有人有想法如何提取只包含加号的字符串?
'grepl( “(?=。* \\ +)”,shopping_list_trim,PERL = T)' – rock321987