平均查询 - mysql的

Question

我有这个疑问

SELECT salary 
    FROM worker W 
    JOIN single_user U ON u.users_id_user = W.single_user_users_id_user 
    JOIN university_has_single_user US ON US.single_user_users_id_user = U.users_id_user 
    JOIN course C ON C.id_course = US.course_id_course 
    JOIN formation_area FA ON FA.id_formation_area = C.formation_area_id_formation_area 
    WHERE FA.area = "Multimédia" 
GROUP BY users_id_user 

......这给了这样的输出：

salary 
-------- 
1400.00 
800.00 

我如何计算这个输出的平均？如果我加：

SELECT round(avg (salary), 0) 

...输出再次是1400.00和800.00，而不是avg（因为group by）。

Answer 1

使用：

SELECT AVG(DISTINCT salary) 
    FROM worker W 
    JOIN single_user U ON u.users_id_user = W.single_user_users_id_user 
    JOIN university_has_single_user US ON US.single_user_users_id_user = U.users_id_user 
    JOIN course C ON C.id_course = US.course_id_course 
    JOIN formation_area FA ON FA.id_formation_area = C.formation_area_id_formation_area 
    WHERE FA.area = "Multimédia" 

由于salary列未包裹在集料，per the documentation, the values you see are arbitrary (can't be guaranteed 100% of the time)。

通常，您需要派生表来获取不同值的平均值，但是需要MySQL's AVG supports using DISTINCT within it。