2
我真的被困在我的项目中的某个点上。我试图将二维数组转换为三维数组。目前I'm在这一点上:三维数组循环
array (size=4)
0 =>
array (size=4)
0 => string 'foo' (length=3)
1 => string 'a' (length=0)
2 => string 'b' (length=0)
3 => string '0' (length=1)
1 =>
array (size=4)
0 => string 'bar' (length=3)
1 => string 'a' (length=0)
2 => string 'b' (length=0)
3 => string '1' (length=1)
2 =>
array (size=4)
0 => string 'bas' (length=3)
1 => string 'a' (length=0)
2 => string 'b' (length=0)
3 => string '1' (length=1)
3 =>
array (size=4)
0 => string 'tas' (length=3)
1 => string 'a' (length=0)
2 => string 'b' (length=0)
3 => string '0' (length=1)
我想这样做的就是用数组的键值新阵列[] [3](我希望这是任何意义上的),所以是这样的:
array (size=2)
0 => array (size=2)
0 => array (size=2)
0 => string 'foo' (length=3)
1 => string 'a' (length=0)
2 => string 'b' (length=0)
1 => array (size=2)
0 => string 'tas' (length=3)
1 => string 'a' (length=0)
2 => string 'b' (length=0)
1 => array (size=2)
0 => array (size=2)
0 => string 'bar' (length=3)
1 => string 'a' (length=0)
2 => string 'b' (length=0)
1 => array (size=2)
0 => string 'bas' (length=3)
1 => string 'a' (length=0)
2 => string 'b' (length=0)
现在这是我可以解释它的最好方法,我不确定我是否有任何意义,或者如果这甚至是可能的,但如果任何人都可以阐明这一点,将非常感谢!
由于提前,
托马斯
非常感谢您! – 2013-04-27 10:28:27