比方说,我有尺寸的这个矩阵m
9×9×26:如何转置Python列表中的3D列表?
[[['a00', ... 'z00'], ['a01', ... 'z01'], ... ['a09', ... 'z09']],
[['a10', ... 'z10'], ['a11', ... 'z11'], ... ['a19', ... 'z19']],
...
[['a90', ... 'z90'], ['a91', ... 'z91'], ... ['a99', ... 'z99']]]
我想皈依尺寸以下矩阵26×81:
[['a00', 'a01', ... 'a09', 'a10', ... 'a19', ... 'a99'],
['z00', 'z01', ... 'z09', 'z10', ... 'z19', ... 'z99']]
什么是最好的方式在Python中做到这一点?
它看起来像你正在寻找的不是转置。转置矩阵就像旋转它。你想[重塑](http://docs.scipy.org/doc/numpy/reference/generated/numpy.reshape.html)它。你可以在这里找到像这样的几个例子[this](http://stackoverflow.com/questions/14476415/reshape-an-array-in-numpy?rq=1)。 – iled
这实际上是一个numpy数组吗? –
对不起,不明确;是的,我想问清楚具体的名单! – Leeren