2013-03-08 88 views
0

我正在为仅存储1位度数的作业分配创建二进制链接列表。我可以获得最高级别,在二进制列表中的任意位置设置位,并返回某个特定级别的位,但由于某种原因,我在创建复制构造函数和赋值(=)操作符时遇到了最大的麻烦。这里是我的代码:复制构造函数和赋值操作符问题

// copy constructor 
// creates a new linked list where the contents are a deep copy of the provided list 
Binary::Binary(const Binary &b) 
{ 
    Binary clone; 
    for(BinaryNode* current_other = b.firstTerm; current_other != nullptr; current_other = current_other->next) 
    { 
     clone.set_bit(1, current_other->degree); 
    } 
} 

// assignment operator 
// sets the current link list to be a deep copy of the provided list. 
// make sure to check if assigning to itself, and make sure to free old memory 
// before making the copy. 
Binary& Binary::operator=(const Binary &other) 
{ 
    Binary clone; 
    for(BinaryNode* current_other = other.firstTerm; current_other != nullptr; current_other = current_other->next) 
    { 
     clone.set_bit(1, current_other->degree); 
    } 
    return clone; 
} 

我的逻辑在这些上是否有缺陷?有人请帮忙!

P.S.我已经测试了我的set_bit(b,d)和其他方法,我知道这些是唯一搞乱的,因为当我尝试“Binary b3(b2)”或“Binary b3 = b2”时,程序停止指出并且“分配1.exe中的0x00DC4B18未处理的异常:0xC0000005:访问冲突读取位置0xCCCCCCD0”。

编辑:我有一个默认的构造,以及: 二进制(){firstTerm = nullptr;}

编辑编辑:

输出:

TESTING DEFAULT CONSTRUCTOR 
    The binary number b1 is empty. 

    TESTING GET AND SET METHODS 
    The highest bit of binary number b1 is 5. 
    The bit of binary number b1 at degree 5 is 1. 
    The bit of binary number b1 at degree 2 is 0. 
    The bit of binary number b1 at degree 1 is 0. 

    TESTING PARAMETER CONSTRUCTOR 
    The bit of binary number b1 at degree 2 is 1. 
    The bit of binary number b1 at degree 0 is 1. 
    The bit of binary number b1 at degree 1 is 0. 

    TESTING COPY CONSTRUCTOR 
    B2 = 101 
    B3 = _ 

Unhandled exception at 0x00C04B18 in Assignment 1.exe: 0xC0000005: Access violation reading location 0xCCCCCCD0. 

仪代码:

#include <iostream> 
#include "binary.h" 

using namespace std; 

int main (void) 
{ 
    // test default constructor 
    Binary b1; 
    cout << "TESTING DEFAULT CONSTRUCTOR" << endl; 
    if (b1.get_degree() == -1) 
     cout << "\tThe binary number b1 is empty." << endl; 
    else 
     cout << "\tThe binary number b1 is NOT empty. (INCORRECT)" << endl; 

    // test get_bit, set_bit, and get_degree 
    cout << "\nTESTING GET AND SET METHODS" << endl; 
    b1.set_bit(1, 2); 
    b1.set_bit(1, 5); 
    b1.set_bit(1, 0); 
    b1.set_bit(0, 2); 
    if (b1.get_degree() == 5) 
     cout << "\tThe highest bit of binary number b1 is 5." << endl; 
    else 
     cout << "\tThe highest bit of binary number b1 is NOT 5. (INCORRECT)" << endl; 
    if (b1.get_bit(5) == 1) 
     cout << "\tThe bit of binary number b1 at degree 5 is 1." << endl; 
    else 
     cout << "\tThe bit of binary number b1 at degree 5 is 0. (INCORRECT)" << endl; 
    if (b1.get_bit(2) == 0) 
     cout << "\tThe bit of binary number b1 at degree 2 is 0." << endl; 
    else 
     cout << "\tThe bit of binary number b1 at degree 2 is 1. (INCORRECT)" << endl; 
    if (b1.get_bit(1) == 0) 
     cout << "\tThe bit of binary number b1 at degree 1 is 0." << endl; 
    else 
     cout << "\tThe bit of binary number b1 at degree 1 is 1. (INCORRECT)" << endl; 

    // test parameter constructor 
    cout << "\nTESTING PARAMETER CONSTRUCTOR" << endl; 
    Binary b2(5); 

    if (b2.get_bit(2) == 1) 
     cout << "\tThe bit of binary number b2 at degree 2 is 1." << endl; 
    else 
     cout << "\tThe bit of binary number b2 at degree 2 is 0. (INCORRECT)" << endl; 
    if (b2.get_bit(0) == 1) 
     cout << "\tThe bit of binary number b2 at degree 0 is 1." << endl; 
    else 
     cout << "\tThe bit of binary number b2 at degree 0 is 0. (INCORRECT)" << endl; 
    if (b2.get_bit(1) == 0) 
     cout << "\tThe bit of binary number b2 at degree 1 is 0." << endl; 
    else 
     cout << "\tThe bit of binary number b2 at degree 1 is 1. (INCORRECT)" << endl; 

    // test copy constructor 
    cout << "\nTESTING COPY CONSTRUCTOR" << endl; 
    cout << "B2= " << b2 << endl; 
    b2.set_bit(1,1); 
    Binary b3(b2); 
    cout << "B3= " << b3 << endl; 
    b2.set_bit(1, 1); 
    cout << "B2= " << b2 << endl; 
    cout << "B3= " << b3 << endl; 
    if (b3.get_bit(2) == 1) 
     cout << "\tThe bit of binary number b3 at degree 2 is 1." << endl; 
    else 
     cout << "\tThe bit of binary number b3 at degree 2 is 0. (INCORRECT)" << endl; 
    if (b3.get_bit(0) == 1) 
     cout << "\tThe bit of binary number b3 at degree 0 is 1." << endl; 
    else 
     cout << "\tThe bit of binary number b3 at degree 0 is 0. (INCORRECT)" << endl; 
    if (b3.get_bit(1) == 0) 
     cout << "\tThe bit of binary number b3 at degree 1 is 0." << endl; 
    else 
     cout << "\tThe bit of binary number b3 at degree 1 is 1. (INCORRECT)" << endl; 

    // test assignment operator 
    cout << "\nTESTING ASSIGNMENT OPERATOR" << endl; 
    b2 = b3; 
    b3.set_bit(1, 1); 

    if (b2.get_bit(2) == 1) 
     cout << "\tThe bit of binary number b2 at degree 2 is 1." << endl; 
    else 
     cout << "\tThe bit of binary number b2 at degree 2 is 0. (INCORRECT)" << endl; 
    if (b2.get_bit(0) == 1) 
     cout << "\tThe bit of binary number b2 at degree 0 is 1." << endl; 
    else 
     cout << "\tThe bit of binary number b2 at degree 0 is 0. (INCORRECT)" << endl; 
    if (b2.get_bit(1) == 0) 
     cout << "\tThe bit of binary number b2 at degree 1 is 0." << endl; 
    else 
     cout << "\tThe bit of binary number b2 at degree 1 is 1. (INCORRECT)" << endl; 

    // test convert 
    cout << "\nTESTING CONVERT METHOD" << endl; 
    if (b1.convert() == 33) 
     cout << "\tThe decimal value of binary number b1 is 33." << endl; 
    else 
     cout << "\tThe decimal value of binary number b1 is NOT 33. (INCORRECT)" << endl; 

    // test output operator 
    cout << "\nTESTING OUTPUT OPERATOR" << endl; 
    cout << "\tThe binary number b1 is " << b1 << endl; 
    cout << "\tThe number b1 should be 100001" << endl; 

    // test addition 
    cout << "\nTESTING ADDITION OPERATOR" << endl; 
    Binary b4 = b2 + b3; 

    if (b4.convert() == 12) 
     cout << "\t101 + 111 = 1100." << endl; 
    else 
     cout << "\t101 + 111 != 1100. (INCORRECT)" << endl; 

    // test subtraction 
    cout << "\nTESTING SUBTRACTION OPERATOR" << endl; 
    Binary b5(b1 - b2); 

    if (b5.convert() == 28) 
     cout << "\t100001 - 101 = 11100." << endl; 
    else 
     cout << "\t100001 - 101 != 11100. (INCORRECT)" << endl; 

    // test multiplication 
    cout << "\nTESTING MULTIPLICATION OPERATOR" << endl; 
    Binary b6 = b3 * b2; 

    if (b6.convert() == 35) 
     cout << "\t111 * 101 = 100011." << endl; 
    else 
     cout << "\t111 * 101 != 100011. (INCORRECT)" << endl; 

    system("pause"); 
} 

binary.h:

#ifndef _BINARY_H_ 
#define _BINARY_H_ 

#include <iostream> 

class Binary { 
private: 
    struct BinaryNode { 
     int degree; 
     BinaryNode* next; 
     BinaryNode(int d, BinaryNode* n): degree(d),next(n) {} 
    }; 
    BinaryNode *firstTerm; 

public: 
    // default constructor 
    Binary() {firstTerm = nullptr;} 

    // constructor 
    // takes a value representing a decimal number and creates 
    // the binary linked list representation of it. 
    Binary(int x); 

    // sets the term with degree d and bit b 
    // notice a node is created if bit is 1 AND a node 
    // for that degree doesn't exist, or the node is removed 
    // if the bit is 0 AND the node with that degree already exists 
    void set_bit(int b, int d); 

    // returns one if a term with degree d exists, zero otherwise 
    int get_bit(int d) const; 

    // returns the decimal integer representation of the binary number. 
    int convert() const ; 

    // returns the highest degree of any term in the binary number 
    // returns -1 if the the list is empty. 
    int get_degree() const; 

    // destructor 
    // make sure that all memory is returned (freed up) correctly 
    ~Binary(); 

    // copy constructor 
    // creates a new linked list where the contents are a deep copy of the provided list 
    Binary(const Binary &b); 

    // assignment operator 
    // sets the current link list to be a deep copy of the provided list. 
    // make sure to check if assigning to itself, and make sure to free old memory 
    // before making the copy. 
    Binary& operator=(const Binary &other); 

    // prints the binary number to the output stream o 
    // please use like:  10001101 
    // terms must be printed in descending order of degree 
    friend std::ostream& operator<<(std::ostream &o, const Binary &b); 

    // returns a new binary number representing the addition of 2 provided binary numbers. 
    // do NOT simply convert the numbers to decimal using convert(),add them, 
    // then convert back to binary. 
    friend Binary operator+(const Binary &b1, const Binary &b2); 

    // returns a new binary number representing the subtraction 
    // of 2 provided binary numbers. can assume b1 will always be 
    // larger than b2. 
    // do NOT simply convert the numbers to decimal using convert(),subtract them, 
    // then convert back to binary. 
    friend Binary operator-(const Binary &b1, const Binary &b2); 

    // returns a new binary number representing the multiplication 
    // of 2 provided binary numbers. 
    // do NOT simply convert the numbers to decimal using convert(),multiply them, 
    // then convert back to binary. 
    friend Binary operator*(const Binary &b1, const Binary &b2); 

}; 

std::ostream& operator<<(std::ostream &o, const Binary &b); 

Binary operator+(const Binary &b1, const Binary &b2); 
Binary operator-(const Binary &b1, const Binary &b2); 
Binary operator*(const Binary &b1, const Binary &b2); 

#endif 

binary.cpp:

#include "binary.h" 
using namespace std; 

// constructor 
// takes a value representing a decimal number and creates 
// the binary linked list representation of it. 
Binary::Binary(int x) 
{ 
    firstTerm = nullptr; 
    int deg = 0; 
    int n = x; 
    while (n != 0) 
    { 
     set_bit(n%2, deg); 
     n = n/2; 
     ++deg; 
    } 
} 

// sets the term with degree d and bit b 
// notice a node is created if bit is 1 AND a node 
// for that degree doesn't exist, or the node is removed 
// if the bit is 0 AND the node with that degree already exists 
void Binary::set_bit(int b, int d) 
{ 
    if (b == 1) 
    { 
     if (firstTerm == nullptr || d == 0) 
      { 
       firstTerm = new BinaryNode(d, firstTerm); 
      } 

     else 
      { 
       BinaryNode *current, *prev = firstTerm; 
       for(current = firstTerm; current != nullptr; current = current->next) 
       { 
        if (current->next == nullptr) 
        { 
         current->next = new BinaryNode(d, nullptr); 
         break; 
        } 
        else if (current->degree == d) 
        { 
         prev->next = new BinaryNode (d, current->next); 
         delete current; 
         break; 
        } 
        else if(current->degree > d) 
        { 
         prev->next = new BinaryNode (d, current); 
         break; 
        } 
        prev = current; 
       } 
      } 
    } 
    else 
    { 
     BinaryNode *current, *prev = firstTerm; 
     for(current = firstTerm; current != nullptr; current = current->next) 
     { 
      if (current->degree == d) 
      { 
       prev->next = current->next; 
       delete current; 
       break; 
      } 
      prev = current; 
     } 
    } 
} 

// returns one if a term with degree d exists, zero otherwise 
int Binary::get_bit(int d) const 
{ 
    for (BinaryNode *current = firstTerm; current != nullptr; current = current->next) 
    { 
     if (current == nullptr) 
      break; 
     if (current->degree == d) 
      return 1; 
    } 
    return 0; 
} 

// returns the decimal integer representation of the binary number. 
int Binary::convert() const 
{ 
    int sum = 0; 
    for (BinaryNode* current = firstTerm; current != nullptr; current = current->next) 
    { 
     sum = sum + (int)pow(2,current->degree); 
    } 
    return sum; 
} 

// returns the highest degree of any term in the binary number 
// returns -1 if the the list is empty. 
int Binary::get_degree() const 
{ 
    if (firstTerm == nullptr) 
     {return -1;} 
    else 
    { 
     BinaryNode *current; 
     for (current = firstTerm; current->next != nullptr; current = current->next); 

     return current->degree; 
    } 
} 

// destructor 
// make sure that all memory is returned (freed up) correctly 
Binary::~Binary() 
{ 
    BinaryNode* tmp; 
    for(BinaryNode* current = firstTerm; current != nullptr; current = tmp) 
    { 
      tmp = current->next; 
      delete current; 
    } 
} 

// copy constructor 
// creates a new linked list where the contents are a deep copy of the provided list 
Binary::Binary(const Binary &b) 
{ 
    for(BinaryNode* current_other = b.firstTerm; current_other != nullptr; current_other = current_other->next) 
    { 
     set_bit(1, current_other->degree); 
    } 
} 

// assignment operator 
// sets the current link list to be a deep copy of the provided list. 
// make sure to check if assigning to itself, and make sure to free old memory 
// before making the copy. 
Binary& Binary::operator=(const Binary &other) 
{ 
    Binary clone; 
    for(BinaryNode* current_other = other.firstTerm; current_other != nullptr; current_other = current_other->next) 
    { 
     clone.set_bit(1, current_other->degree); 
    } 
    return clone; 
} 

// prints the binary number to the output stream o 
// please use like:  10001101 
// terms must be printed in descending order of degree 
std::ostream& operator<<(std::ostream &o, const Binary &b) 
{ 
    for(int i = b.get_degree(); i >= 0; --i) 
    { 
     o << b.get_bit(i); 
    } 
    return o; 
} 

// returns a new binary number representing the addition of 2 provided binary numbers. 
// do NOT simply convert the numbers to decimal using convert(),add them, 
// then convert back to binary. 
Binary operator+(const Binary &b1, const Binary &b2) 
{ 
    int l = b1.get_degree(); 
    if (b1.get_degree() < b2.get_degree()) 
    { 
     l = b2.get_degree(); 
    } 
    int i, c = 0; 
    Binary sum; 
    for (i = 0; i <= l; ++i) 
    { 
     sum.set_bit(((b1.get_bit(i)^b2.get_bit(i))^c), i); //get sum (A XOR B XOR C) 
     c = ((b1.get_bit(i) & b2.get_bit(i)) | (b1.get_bit(i) &c)) | (b2.get_bit(i) & c); //get carry bit (AB + BC + CA) 
    } 
    sum.set_bit(c, i); 
    return sum; 
} 

// returns a new binary number representing the subtraction 
// of 2 provided binary numbers. can assume b1 will always be 
// larger than b2. 
// do NOT simply convert the numbers to decimal using convert(),subtract them, 
// then convert back to binary. 
Binary operator-(const Binary &b1, const Binary &b2) 
{ 
    Binary one = Binary(1); 
    Binary inv, two, result, fresult; 
    int i, l = b2.get_degree() + 1; 
    for(i = 0; i <= l; ++i) 
    { 
     if (b2.get_bit(i) == 1) 
      inv.set_bit(0,i); 
     else 
      inv.set_bit(1,i); 
    } 
    two = inv + one; 
    result = two + b1; 
    if (b1.get_degree() > l) 
    { 
     l = b1.get_degree(); 
    } 
    for (l; l >= 0; l--) 
    { 
     fresult.set_bit(result.get_bit(l), l); 
    } 
    return (fresult); 
} 

// returns a new binary number representing the multiplication 
// of 2 provided binary numbers. 
// do NOT simply convert the numbers to decimal using convert(),multiply them, 
// then convert back to binary. 
Binary operator*(const Binary &b1, const Binary &b2) 
{ 
    Binary prod = b1; 
    for (int i = 1; i < b2.convert(); ++i) 
    { 
     prod = prod + b1; 
    } 
    return prod; 
} 
+0

我相信对于operator =使用这个指针而不是制作一个新的Binary并克隆它。 – 2013-03-08 19:04:00

+0

你是否定义了一个默认构造函数? (一个不带任何参数的构造函数) – Roberto 2013-03-08 19:07:43

+0

我们需要您的完整课程来帮助您... – Roberto 2013-03-08 21:02:51

回答

1

我想通了,谢谢大家的帮助。我想出了我的问题。在复制构造函数中,正如有人指出的那样,我相信,我还没有声明firstTerm,因为我必须在其他构造函数中声明。最后的代码最终为:

Binary::Binary(const Binary &b) 
{ 
    firstTerm = nullptr; //construct firstTerm 
    for(BinaryNode* current_other = b.firstTerm; current_other != nullptr; current_other = current_other->next) 
    //set a node pointer = to b's firstTerm then go through b's list, setting each bit and degree to the new list 
    { 
     set_bit(1, current_other->degree); //only 1 bits exist in this list, so you'll only set one bits at each degree 
    } 
} 

在赋值运算符,我不是第一次破坏当前目录,如果需要的话,或者确保它没有被复制到自身。另外,我在错误的地方有&。最后的代码结束为:

Binary &Binary::operator=(const Binary &other) 
{ 
    if(this != &other) //make sure it isn't copying to itself 
    { 
     if (this->get_degree() != -1) //if the Binary list isn't empty, destruct it 
     { 
      this->~Binary(); 
     } 
     firstTerm = nullptr; //construct firstTerm 
     for(BinaryNode* current_other = other.firstTerm; current_other != nullptr; current_other = current_other->next) 
     //set a node pointer = to other's firstTerm then go through other's list, setting each bit and degree to the new list 
     { 
      set_bit(1, current_other->degree); //only 1 bits exist in this list, so you'll only set one bits at each degree 
     } 

     return *this; 
    } 
} 
3
Binary::Binary(const Binary &b) 
{ 
    Binary clone; 
    for(BinaryNode* current_other = b.firstTerm; current_other != nullptr; current_other = current_other->next) 
    { 
     clone.set_bit(1, current_other->degree); 
    } 
} 

您创建一个对象称为clone,设置其位,然后把它扔掉。这看起来不正确。也许你的意思是:

Binary::Binary(const Binary &b) 
{ 
    for(BinaryNode* current_other = b.firstTerm; current_other != nullptr; current_other = current_other->next) 
    { 
     set_bit(1, current_other->degree); 
    } 
} 
+0

我也试过,但它也不起作用... – 2013-03-08 19:17:46

+0

“它不起作用”不是一个有帮助的问题描述。它是否编译?它运行吗?你期待什么结果?你得到了什么? (你也有一个与'operator ='类似的问题 - 它不会修改它被调用的对象,这是这样的操作符通常会做的。) – 2013-03-08 19:18:46

+0

对不起,我急着去工作。当我以另一种方式拥有它时,它会给我带来同样的错误。该程序编译,但是当我尝试对复制的二进制列表执行任何操作时,它会在原始文章中发布“访问冲突读取”错误。 例如,在main()中,我有: Binary b3(b2); cout << b3 << endl; 在这一点上,在输出,它打破了,但事先预先工作。我会在上面发布我的整个代码。 – 2013-03-09 03:34:52

0

一个一旦你定义构造函数,编译器将不会为你生成一个默认的构造,这意味着你不能做Binary clone;如果你还没有定义的Binary::Binary()构造。

+0

我也有一个默认构造函数: Binary(){firstTerm = nullptr;} – 2013-03-08 19:14:29

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