如何防止DataGridView双击多次打开窗体？

当我双击dataGridView单元格时，如何一次打开窗体？如何防止DataGridView双击多次打开窗体？

private void dataGridView1_CellMouseDoubleClick(object sender, DataGridViewCellMouseEventArgs e) 
{ 
    //string queryString = "SELECT id, thename, address,fax,mobile,email,website,notes FROM movie"; 
    int currentRow = int.Parse(e.RowIndex.ToString()); 
    try 
    { 
     string movieIDString = dataGridView1[0, currentRow].Value.ToString(); 
     movieIDInt = int.Parse(movieIDString); 
    } 
    catch (Exception ex) { } 
    // edit button 
    if (e.RowIndex != -1) 
    { 
     string id = dataGridView1[0, currentRow].Value.ToString(); 
     string thename = dataGridView1[1, currentRow].Value.ToString(); 
     string address = dataGridView1[2, currentRow].Value.ToString(); 
     string fax = dataGridView1[3, currentRow].Value.ToString(); 
     string mobile = dataGridView1[4, currentRow].Value.ToString(); 
     string email = dataGridView1[5, currentRow].Value.ToString(); 
     string website = dataGridView1[6, currentRow].Value.ToString(); 
     string notes = dataGridView1[7, currentRow].Value.ToString(); 

     Form4 f4 = new Form4(); 

     f4.id = movieIDInt; 
     f4.thename = thename; 
     f4.address = address; 
     f4.fax = fax; 
     f4.mobile = mobile; 
     f4.email = email; 
     f4.website = website; 
     f4.notes = notes; 


     f4.Show(); 
    } 
}

这个代码打开一个表格，每次我点击一个DataGridView，我想，如果它被打开，DoubleClick就不会再次打开它

来源

2011-08-11 amer

是您曾经参与过Click事件处理程序或DoubleClick事件处理程序的代码（或CellClick或CellDoubleClick ...）？ – digEmAll

dataGridView1_CellMouseDoubleClick – amer

将打开的表单保留在类字段
例如，而不是你的代码，这样调用一个方法：

Form4 f4 = null; // class field 

    // call this method when cellMouseDoubleClick is triggered 
    private void OpenForm4IfNotOpened() 
    { 
     if (f4 == null || f4.IsDisposed) 
     { 
      f4 = new Form4(); 

      f4.id = movieIDInt; 
      f4.thename = thename; 
      f4.address = address; 
      f4.fax = fax; 
      f4.mobile = mobile; 
      f4.email = email; 
      f4.website = website; 
      f4.notes = notes; 
      f4.Show(); 
     } 
     else 
     { 
      f4.BringToFront(); 
     } 
    }

来源

2011-08-11 08:45:02 digEmAll

digEmAll谢谢:) – amer

@amer：不客气。无论如何，你应该接受你认为是正确的答案（不仅在这里，而且在你的问题之前），因为这是StackOverflow的工作原理;-) [（链接：如何接受答案）]（http：// meta。 stackexchange.com/questions/5234/how-does-accepting-an-answer-work） – digEmAll

声明此为form.cs一个全局变量

bool isopened = false;

然后用isopened可变检查

if (isopened == false) 
      { 
       FormInitialSettings(); 
       Form4 f4 = new Form4(); 

       f4.id = movieIDInt; 
       f4.thename = thename; 
       f4.address = address; 
       f4.fax = fax; 
       f4.mobile = mobile; 
       f4.email = email; 
       f4.website = website; 
       f4.notes = notes; 
       isopened = true; 
       f4.Show(); 
      }

来源

2011-08-11 08:41:31 Nighil

最好的办法是使变量F4一个L级evel变量和行Form4 f4 = new Form4();应该只运行一次，然后行f4.Show();测试，以查看表单是否已显示，然后再试图显示它。

来源

2011-08-11 08:43:18

如何防止DataGridView双击多次打开窗体？

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