2016-02-09 228 views
0

IM在SQL Server 2008中的工作,我想连接两个字符串,条件是SQL连接字符串

@str1 = 'A1,B1,C1' 
@str2 = 'A2,B2,C2' 

我想要的结果作为

@result = 'A1,A2,B1,B2,C1,C2' 

请帮助...

+1

'设置@result = @ STR1 + '' + @ str2' –

+0

我想要'A1,A2,B1,B2,C1,C2'...与你的答案一样,将会产生像'A1,B1,C1,A2,B2,C2' – user2695128

+1

你必须使用splitter功能来做到这一点。 Google s * ql服务器拆分字符串* –

回答

1

您存储数据的方式是非常糟糕的做法。不过这里是训练目的的解决方案:

DECLARE 
    @str1 varchar(30) = 'A1,B1,C1', 
    @str2 varchar(30) = 'A2,B2,C2', 
    @result varchar(60) 

;WITH split as 
(
    SELECT t.c.value('.', 'VARCHAR(2000)') x 
    FROM (
     SELECT x = CAST('<t>' + 
      REPLACE(@str1 + ',' + @str2, ',', '</t><t>') + '</t>' AS XML) 
) a 
CROSS APPLY x.nodes('/t') t(c) 
) 
SELECT 
    @result = 
    STUFF(( 
     SELECT ',' + x 
     FROM split 
     ORDER BY x 
     for xml path(''), type 
     ).value('.', 'varchar(max)'), 1, 1, '') 

SELECT @result 

结果:

A1,A2,B1,B2,C1,C2 
1

首先创建一个拆分功能来让你的项目分开:

CREATE FUNCTION [dbo].[Split] 
(
    @String NVARCHAR(4000), 
    @Delimiter NCHAR(1) 
) 
RETURNS TABLE 
AS 
RETURN 
(
    WITH Split(stpos,endpos) 
    AS(
     SELECT 0 AS stpos, CHARINDEX(@Delimiter,@String) AS endpos 
     UNION ALL 
     SELECT endpos+1, CHARINDEX(@Delimiter,@String,endpos+1) 
      FROM Split 
      WHERE endpos > 0 
    ) 
    SELECT 'Id' = ROW_NUMBER() OVER (ORDER BY (SELECT 1)), 
     'Data' = SUBSTRING(@String,stpos,COALESCE(NULLIF(endpos,0),LEN(@String)+1)-stpos) 
    FROM Split 
) 
GO 

现在你可以先拆分再和订购您的结果,然后CONCAT值

DECLARE @DelimitedString NVARCHAR(128) 
SET @DelimitedString = @str1 + ',' + @str2 
SELECT @result = COALESCE(@result + ',', '') +Data 
    FROM (SELECT Data 
      FROM dbo.Split(@DelimitedString, ',') 
     ORDER BY Data) 
0
SET @result = @str1 + ',' + @str2 
SELECT @result 

更新1

我认为最好的办法将是首先得到充分的字符串,然后用逗号分割它,然后将其存储在临时表中,然后进行排序,可能是一个好主意。

CREATE FUNCTION SplitString 
( 
     @Input NVARCHAR(MAX), 
     @Character CHAR(1) 
) 
RETURNS @Output TABLE (
     Item NVARCHAR(1000) 
) 
AS 
BEGIN 
     DECLARE @StartIndex INT, @EndIndex INT 

     SET @StartIndex = 1 
     IF SUBSTRING(@Input, LEN(@Input) - 1, LEN(@Input)) <> @Character 
     BEGIN 
      SET @Input = @Input + @Character 
     END 

     WHILE CHARINDEX(@Character, @Input) > 0 
     BEGIN 
      SET @EndIndex = CHARINDEX(@Character, @Input) 

      INSERT INTO @Output(Item) 
      SELECT SUBSTRING(@Input, @StartIndex, @EndIndex - 1) 

      SET @Input = SUBSTRING(@Input, @EndIndex + 1, LEN(@Input)) 
     END 

     RETURN 
END 
GO 


SELECT Item FROM 
dbo.SplitString(@result,',') ORDER BY Item 
+0

我想要这种格式'A1,A2,B1,B2,C1,C2' – user2695128

+0

@ user2695128请检查我的更新 – Hemal

0

尝试:

SELECT stuff((SELECT ',' + T.str FROM 
(SELECT 
    PARSENAME(REPLACE(@str1,',','.'),1) str UNION ALL 
    PARSENAME(REPLACE(@str1,',','.'),2) str UNION ALL 
    PARSENAME(REPLACE(@str1,',','.'),3) str UNION ALL 
    PARSENAME(REPLACE(@str2,',','.'),1) str UNION ALL 
    PARSENAME(REPLACE(@str2,',','.'),2) str UNION ALL 
    PARSENAME(REPLACE(@str2,',','.'),3) str)T 
    ORDER BY T.str 
FOR XML PATH('')),1,1,'') 
+0

非常感谢你.....这工作正常 – user2695128

+0

@ user2695128:欢迎,如果它是为你工作,你可以把它标记为答案 –