我有一个排行榜,它告诉我什么人与他们的货币(虚拟货币为测试目的)ontop。 所以它的工作原理,它显示了从我的表到PDO(PHP数据对象)的一切。我的pdo结果复制到表
问题是,我让它在表中输出。但对于每一个ID那里有正在取得第二表是这样的:
代码即时通讯使用:
<?php
$db = new PDO('mysql:host=localhost;dbname=test1','root','####');
$sql = "SELECT naam, id, days, money FROM user ORDER BY money DESC ";
$results = $db->query($sql);
foreach($results as $row)
{
?>
<html>
<head>
</head>
<body>
<TABLE BORDER="5" WIDTH="100%" CELLPADDING="4" CELLSPACING="3">
<TR>
<TH><BR><H3>POINTS LEADERBOARD</H3>
</TH>
</TR>
<TR>
<TH>Username</TH>
<TH>Money</TH>
<TH>Days</TH>
</TR>
<TR>
<TD><?php echo $row['naam']; ?></TD>
<TD><?php echo $row['money']?></TD>
<TD><?php echo $row['days']?></TD>
</TR>
</TABLE>
<?php
/*
echo "<table>";
echo "<TR>";
echo "<TH><BR><H3>POINTS LEADERBOARD</H3>";
echo "</TH>";
echo "</TR>";
echo "<TR>";
echo "<TH>Username</TH>";
echo "<TH>Money</TH>";
echo "<TH>Days</TH>";
echo "</TR>";
echo "<TR>";
echo "<TD>"; echo $row['naam']; echo "</TD>";
echo "<TD>"; echo $row['money']; echo "</TD>";
echo "<TD>"; echo $row['days']; echo "</TD>";
echo "</TR>";
echo "</table>";
*/
?>
<?php } ?>
</body>
</html>
谁能帮助我,或告诉我什么即时做错了什么?
谢谢!
请告诉周围的HTML代码,例如循环 – Steve
不能为整个脚本 – RamRaider
不,我现在 –