基本的T-sql问题

我有一个邀请表。喜欢这个;基本的T-sql问题

Email   CreateDate 
[email protected]  2011-03-04 10:10:46.273 
[email protected]  2011-03-10 12:06:26.673 
[email protected]  2011-03-20 12:06:26.673 
[email protected]  2011-03-10 12:06:26.673

如何返回？

[email protected]  2011-03-04 10:10:46.273 1 
[email protected]  2011-03-10 12:06:26.673 1 
[email protected]  2011-03-20 12:06:26.673 2

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2011-04-07 ozkank

这可以由许多人在这里回答。你写了什么SQL？ – shahkalpesh 2011-04-07 07:14:43

确实是“基本”。你有什么尝试？ – RichardTheKiwi 2011-04-07 07:23:35

SELECT Email, Max(CreateDate), Count(CreateDaate) FROM YourTable Group By Email.

来源

2011-04-07 07:15:24

select Email, max(CreateDate), count(*) 
from Invitation 
group by Email

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2011-04-07 07:15:59 mousio

您可以使用下面的复杂其一也。因此你可以通过子句学习分区。

select a.email,max(Date),max(a.rn) from (select email,date,ROW_NUMBER() over(partition by email order by email)rn from #a)a group by email

来源

2011-04-07 11:45:41 Luniam

基本的T-sql问题

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