计算.txt输入文件中的字符串出现次数

Question

输入文件以这种方式每次有一行数据：第1行：字符串，第2-4行：整数，第5行：字符串等我需要计数字符串的总数并忽略整数。我怎么能这样做？这里是我的代码：

import java.util.Scanner; 
import java.io.*; 
public class Project5 { 

public static void main(String[] args) { 
    Scanner in = new Scanner(System.in); 
    System.out.println("Enter the file name: "); 
    String fileName = in.nextLine(); 
    int stringCounter = 0; 
    try { 
     File file = new File(fileName); 
     Scanner inputFile = new Scanner(file); 
     String SnumStudents = inputFile.nextLine(); 
     int numStudents = Integer.parseInt(SnumStudents); 
     Student [] studentList = new Student[numStudents]; 
     for (int i = 0; i < numStudents; i++) 
     { 
      String line = inputFile.nextLine(); 
      String score1 = inputFile.nextLine(); 
      String score2 = inputFile.nextLine(); 
      String score3 = inputFile.nextLine(); 
      studentList [i] = new Student(line, Integer.parseInt(score1), Integer.parseInt(score2), Integer.parseInt(score3)); 
     } 
     System.out.println("Name\t\tScore1\tScore2\tScore3\tTotal"); 
     System.out.println("---------------------------------------------"); 
     for (int i=0; i< studentList.length;i++){ 
      System.out.println(studentList[i].getName() + "\t" + studentList[i].getScore1() + "\t" + studentList[i].getScore2() + "\t" + studentList[i].getScore3() + "\t" + studentList[i].getTotal()); 
     } 
     System.out.println("---------------------------------------------"); 
     Integer i = Integer.valueOf(SnumStudents); 
     stringCounter++; 
     System.out.println(stringCounter); 
     inputFile.close(); 
    } catch (IOException e) { 
     System.out.println("There was a problem reading from " + fileName); 
    } 
    finally { 
    } 
    in.close(); 
} 
} 

输入文件：

9 
Andy Borders 
200 
250 
400 
John Smith 
120 
220 
330 
Alvin Smith 
225 
300 
278 

Answer 1

一个可行的办法（伪代码）

1. 初始化计数器（跟踪弦数）

   int stringCounter = 0; 
   

2. 使用Reader or a Scanner

   Scanner scan = new Scanner(file); 
   

3. 遍历每一行，并确定是否行是一个数字，试图一旦退出循环解析值

   while(scan.hasNext()) { 
       String currentLine = scan.nextLine(); 
       try { 
        Integer i = Integer.valueOf(currentLine); 
       } catch (NumberFormatException nfe) { 
        stringCounter++; 
       } 
   } 
   

4. 您的计数器将有答案