如何检查字符串是否不等于所有这些？

Question

试图改写这个使用LINQ：

if (mode != "A" && mode != "B" && mode != "C" && mode != "D" && mode != "E" && mode != "F" && mode != "G") 
{ 
    continue; 
} 

什么是重构这个最简洁明了的方式吗？我可以发誓我之前看过这样的帖子，但目前我找不到它。

Answer 1

您可以使用从IList<T>Contains方法：

IList<string> modes = new[]{"A","B","C","D","E","F","G"}; 
if (!modes.Contains(mode))... 

Answer 2

var modes = new[] { "A","B","C","D","E","F","G"}; 

if (modes.All(a => mode != a)) 
    continue; 

Answer 3

编写扩展方法的字符串类

public static bool In(this string s, params string[] values) 
{ 
    return values.Any(x => x.Equals(s)); 
} 

调用它以这种方式

if (!mode.In("A", "B", "C", "D","E","F", "G") 
{ 
    continue; 
} 

Answer 4

我ü SE这种扩展方法所有的时间

public static bool IsIn(this string source, params string[] parms) 
{ 
    return parms.Contains(source); 
} 

而且按如下方式使用它：

if (!mode.IsIn("A", "B", "C", "D", "E", "F", "G")) 
{ 
    continue; 
} 

下一步，如果你使用它了，是

public static bool IsNotIn(this string source, params string[] parms) 
{ 
    return !IsIn(source, params); 
} 

，你会得到略更具可读性

if (mode.IsNotIn("A", "B", "C", "D", "E", "F", "G")) 
{ 
    continue; 
} 

Answer 5

string s = "ABCDEFG"; 
bool res = s.Any(item => { return (int)item > 64 && (int)item < 72; });