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我的表单HTML源代码如下,我试图“检查其中一个复选框”并点击“更新”或使用机械化提交按钮。我将如何去做这件事? linear_entitlements的变量是否无法实现?Python机械化提交表单数据
<form accept-charset="UTF-8" action="/admin/users/3548003/user_linear_entitlements" class="form with-border" id="edit_user_3548003" method="post"><div style="margin:0;padding:0;display:inline"><input name="utf8" type="hidden" value="✓"><input name="_method" type="hidden" value="put"><input name="authenticity_token" type="hidden" value="samplevalue"></div>
<table class="table table-striped">
<thead>
<tr>
<th>Name</th>
<th>GUID</th>
<th>CMS Subpack ID</th>
<th>Last Updated</th>
</tr>
</thead>
<tbody>
<tr id="linear_entitlement_1">
<td>
<div class="control-group">
<label class="checkbox">
<span>SUN Pack</span>
<input class="checkbox" id="user_linear_entitlement_ids_" name="user[linear_entitlement_ids][]" type="checkbox" value="1">
</label>
</div>
</td>
<td> 2a59739c-13ed-11e2-a36b-12313d298802 </td>
<td> 1 </td>
<td> 2014-02-12 21:32:56 UTC <div style="float:right"><a href="/admin/linear_entitlements/1">→</a></div></td>
</tr>
<tr id="linear_entitlement_7">
<td>
<div class="control-group">
<label class="checkbox">
<span>Tamil Pack - Legacy</span>
<input class="checkbox" id="user_linear_entitlement_ids_" name="user[linear_entitlement_ids][]" type="checkbox" value="7">
</label>
</div>
</td>
<td> 2ab298dc-13ed-11e2-a36b-12313d298802 </td>
<td> 3 </td>
<td> 2015-04-01 23:11:33 UTC <div style="float:right"><a href="/admin/linear_entitlements/7">→</a></div></td>
</tr>
</tbody>
</table>
<div class="form-actions">
<input class="btn primary input_submit" name="commit" type="submit" value="Update"> <button type="reset" class="btn">Cancel</button>
</div>
</form>
到目前为止,我有这个,它选择的形式:
htmlResponse2 = browser.open(URL + 'admin/users/' + old_user_url + '/edit')
browser.select_form(nr=0)
它说,它无法找到复选框,也许我选择的形式不正确。 –
哦这里... type =“checkbox” 打印表格然后打印find_control进行调试以帮助您。 –