mysql日报表查询

Question

以下查询向我提供设备租赁公司的项目报告。这是一个超级复杂的查询，需要将近20秒才能运行。这显然不是获取我正在查找的数据的正确方法。我从PHP构建这个查询，并在02-01-2011的开始日期和03-01-2011的结束日期，产品代码（p_code = 1）和产品池（i_pool = 1）中添加。这4条信息被传递给一个PHP函数，并注入到下面的sql中，以返回我需要的报表，以显示日历控件显示的项目数。我的问题是：是否有任何方法可以更好地简化或改进，或者更有效地运行，使用更好的连接或更好的方式来显示个别日子。

SELECT DISTINCT reportdays.reportday, count(*) 
FROM 
(SELECT '2011-02-01' + INTERVAL a + b DAY reportday 
FROM 
(SELECT 0 a UNION SELECT 1 a UNION SELECT 2 UNION SELECT 3 
    UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7 
    UNION SELECT 8 UNION SELECT 9) d, 
(SELECT 0 b UNION SELECT 10 UNION SELECT 20 
    UNION SELECT 30 UNION SELECT 40) m 
WHERE '2011-02-01' + INTERVAL a + b DAY < '2011-03-01' 
ORDER BY a + b) as reportdays 
JOIN rental_inv as line 
    ON DATE(FROM_UNIXTIME(line.ri_delivery_dte)) <= reportdays.reportday 
    AND DATE(FROM_UNIXTIME(line.ri_pickup_dte)) >= reportdays.reportday 
LEFT OUTER JOIN rental_in as rent on line.ri_num = rent.ri_num 
LEFT OUTER JOIN rental_cancels cancelled on rent.ri_num = cancelled.ri_num 
LEFT OUTER JOIN inv inventory on line.i_num = inventory.i_num 
LEFT OUTER JOIN product ON inventory.p_code = product.p_code 
WHERE rent.ri_extend = 0  -- disregard extended rentals 
    AND cancelled.ri_num is null -- disregard cancelled rentals 
    AND inventory.p_code = 1 
    AND inventory.i_pool = 1 

GROUP BY reportdays.reportday 

如果有任何其他信息需要，让我知道，我会发布它。

Answer 1

您可以使用：

SELECT DATE(ri_delivery) as day, 
     count(*) as itemsout, 
    FROM rental_inv 
GROUP BY day; 

我不知道，如果你需要这样或不同的事情。

SELECT dates.day, count (*) 
    FROM rental_inv line 
     INNER JOIN (SELECT DATE(ri_delivery_dte) as day FROM rental_inv 
         WHERE ri_delivery_dte >= '2011/02/01' 
         AND ri_delivery_dte <= '2011/02/28' 
        GROUP BY day 
        UNION 
        SELECT DATE(ri_pickup_dte) as day FROM rental_inv 
         WHERE ri_pickup_dte >= '2011/02/01' 
         AND ri_pickup_dte <= '2011/02/28' 
        GROUP BY day) dates 
       ON line.ri_delivery_dte <= dates.day and line.ri_pickup_dte >= dates.day 
      LEFT JOIN rental_cancels canc on line.ri_num = canc.ri_num 
      LEFT JOIN rental_in rent on line.ri_num = rent.ri_num 
    WHERE canc.ri_num is null 
     AND rent.ri_extend = 0 
GROUP BY dates.day 

Answer 2

，找到所有天：

SELECT DATE（IFNULL（ri_delivery，ri_pickup））AS date FROM rental_inv AS dateindex WHERE [年 - 月 - 1] = < ri_delivery < = LAST_DAY（[年 - MONTH-1]）OR [年 - 月 - 1] = < ri_pickup < = LAST_DAY（[年 - 月 - 1]）GROUP BY date具有不ISNULL（date）

寻找项目出

SELECT COUNT（id）FROM rental_inv WHERE ri_pickup = [DATE]; 查找项目

SELECT COUNT（id）FROM rental_inv WHERE ri_delivery = [DATE]; 找到平衡

SELECT COUNT（out.id） - COUNT（in.id）FROM rental_inv AS出INNER JOIN rental_inv AS在 ON DATE（out.ri_pickup）= DATE（in.ri_delivery）WHERE out.ri_pickup = [DATE] OR in.ri_delivery = [DATE]

你可能会加入一切，但自其程序以来更清楚;

Answer 3

我不确定这是否是您的问题的确切答案，但我会做这样的事情，我猜。 （我没有使用任何SQL编辑器，所以你需要检查我猜的语法）

SELECT 
    reportdays.d3 as d, 
    (COALESCE(outgoing.c1,0) - COALESCE(incoming.c2,0)) as c 
FROM 
-- get report dates 
(
    SELECT DATE(FROM_UNIXTIME(COALESCE(l3.ri_delivery_dte, l3.ri_pickup_dte)) d3 
    FROM rental_inv l3 
    WHERE 
     (l3.ri_delivery_dte >= UNIX_TIMESTAMP('2011-02-01') 
      AND l3.ri_delivery_dte < UNIX_TIMESTAMP('2011-03-01')) 
     OR (l3.ri_pickup_dte >= UNIX_TIMESTAMP('2011-02-01') 
      AND l3.ri_pickup_dte < UNIX_TIMESTAMP('2011-03-01')) 
    GROUP BY d3 
) as reportdays 
-- get outgoing 
LEFT JOIN ( 
    SELECT DATE(FROM_UNIXTIME(l1.ri_delivery_dte)) as d1, count(*) as c1 
    FROM rental_inv l1 
    LEFT JOIN rental_cancels canc1 on l.ri_num = canc1.ri_num 
    LEFT JOIN rental_in rent1 on l.ri_num = rent1.ri_num 
    WHERE 
     l1.ri_delivery_dte >= UNIX_TIMESTAMP('2011-02-01') 
     AND l1.ri_delivery_dte < UNIX_TIMESTAMP('2011-03-01') 
     AND canc1.ri_num is null 
     AND rent1.ri_extend = 0 
    GROUP BY d1 
) as outgoing ON reportdays.d3 = outgoing.d1 
-- get incoming 
LEFT JOIN ( 
    SELECT DATE(FROM_UNIXTIME(l2.ri_pickup_dte)) as d2, count(*) as c2 
    FROM rental_inv l2 
    LEFT JOIN rental_cancels canc2 on l2.ri_num = canc2.ri_num 
    LEFT JOIN rental_in rent2 on l2.ri_num = rent2.ri_num 
    WHERE 
     l2.ri_pickup_dte >= UNIX_TIMESTAMP('2011-02-01') 
     AND l2.ri_pickup_dte < UNIX_TIMESTAMP('2011-03-01') 
     AND canc2.ri_num is null 
     AND rent2.ri_extend = 0 
    GROUP BY d2 
) as incoming ON reportdays.d3 = incoming.d2