2017-04-10 63 views
0

我试图从提交到电子邮件地址的表单输入字段发送数据,同时表单数据被插入到数据库表中。我已成功地设法将表单数据提交到数据库中,我现在正努力将表单数据作为电子邮件发送。这是我的下面的PHP代码。所有的PHP代码都在一个文件中。我试图将数据发送到的电子邮件地址不是Gmail,Hotmail等电子邮件,它是公司自己的邮寄地址。发送申请表并提交并插入到数据库中

<?php 
$conn = mysqli_connect("", "", "", ""); --> deleted this because of this post 

if (!$conn) { 

die ("Connection failed: ". mysqli_connect_error()); 

} 

$course = $_POST ['course']; 
$firstname = $_POST ['firstname']; 
$surname = $_POST ['surname']; 
$DOB = $_POST ['DOB']; 
$gender = $_POST ['gender']; 
$address1 = $_POST ['address1']; 
$address2 = $_POST ['address2']; 
$city = $_POST ['city']; 
$postcode = $_POST ['postcode']; 
$mobile = $_POST ['mobile']; 
$home = $_POST ['home']; 
$email = $_POST ['email']; 
$residency = $_POST ['residency']; 
$learning = $_POST ['learning']; 
$qualifications = $_POST ['qualifications']; 

$sql = "INSERT INTO form (course, firstname, surname, DOB, gender, address1, address2, city, postcode, mobile, home, email, residency, learning, qualifications) VALUES ('$course', '$firstname', '$surname', '$DOB', '$gender', '$address1', '$address2', '$city', '$postcode', '$mobile', '$home', '$email', '$residency', '$learning', '$qualifications')"; 

$result = mysqli_query($conn, $sql); 

以上是代码来获取表单数据到数据库中。下面的代码是我尝试将信息发送到一个电子邮件地址。

if(isset($_POST["submit"])){ 
// Checking For Blank Fields.. 
if(
    $_POST["course"]==""||          $_POST["firstname"]==""||          
    $_POST["surname"]==""|| 
    $_POST["DOB"]==""|| 
    $_POST["gender"]==""|| 
    $_POST["address1"]==""|| 
    $_POST["address2"]==""|| 
    $_POST["city"]==""|| 
    $_POST["postcode"]==""|| 
    $_POST["mobile"]==""|| 
    $_POST["home"]==""|| 
    $_POST["email"]==""||              
    $_POST["residency"]==""||              
    $_POST["learning"]==""||              
    $_POST["qualifications"]=="") 
{ 
    echo "Please ensure all fields are filled in."; 
} else { 
// Check if the "Sender's Email" input field is filled out 
$email=$_POST['email']; 
// Sanitize E-mail Address 
$email =filter_var($email, FILTER_SANITIZE_EMAIL); 
// Validate E-mail Address 
$email= filter_var($email, FILTER_VALIDATE_EMAIL); 
if (!$email){ 
echo "Invalid Email"; 
} 
else{ 

$course = $_POST['course']; 
$firstname = $_POST['firstname']; 
$surname = $_POST['surname']; 
$DOB = $_POST['DOB']; 
$gender = $_POST['gender']; 
$address1 = $_POST['address1']; 
$address2 = $_POST['address2']; 
$city = $_POST['city']; 
$postcode = $_POST['postcode']; 
$mobile = $_POST['mobile']; 
$home = $_POST['home']; 
$email = $_POST['email']; 
$residency = $_POST['residency']; 
$learning = $_POST['learning']; 
$qualifications = $_POST['qualifications']; 

$headers = 'From:'. $email . "\r\n"; // Sender's Email 
$headers .= 'Cc:'. $email . "\r\n"; // Carbon copy to Sender 

// Send Mail By PHP Mail Function 
mail("[email protected]", $course, $firstname, $surname, $DOB, $gender, $address1, $address2, $city, $postcode, $mobile, $home, $email, $residency, $learning, $qualifications); 
echo "Your mail has been sent successfuly! We will get back to as soon as we can!"; 
     } 
    } 
} 

header("Location: apply.php"); 

以下是只是在我的HMTL标签的第一部分:

<form class="form" id="contact_form" action="submitApplication.php" method="post"> 

提交按钮:

<button type="submit" name="submit" class="btn btn-primary btn-lg outline hvr-grow">Submit Application</button> 

一些补充,当我尝试提交申请将上面的所有代码都放在一个文件中,在提交时,没有数据被发送到数据库,同时在同一个文件中使用电子邮件的代码。如果我删除同一文件中的电子邮件的代码,则将申请表提交给数据库。我必须尽可能简洁,并希望有人能帮助我!谢谢!

+0

这表明你在电子邮件代码语法错误。打开PHP错误报告并查看那里显示的内容。 –

+0

此外,您的代码易受SQL注入的影响。请使用mysqli –

+0

准备好的语句[Little Bobby](http://bobby-tables.com/)表示*** [您的脚本存在SQL注入攻击风险。](http://stackoverflow.com/questions/) 60174/how-can-i-prevent-sql -injection-in-php)***了解[MySQLi](http:/ /)的[prepared](http://en.wikipedia.org/wiki/Prepared_statement) /php.net/manual/en/mysqli.quickstart.prepared-statements.php)。即使[转义字符串](http://stackoverflow.com/questions/5741187/sql-injection-that-gets-around-mysql-real-escape-string)是不安全的! –

回答

0

按这条线:

mail("[email protected]", $course, $firstname, $surname, $DOB, $gender, $address1, $address2, $city, $postcode, $mobile, $home, $email, $residency, $learning, $qualifications); 

这不是如何mail()工作http://php.net/manual/en/function.mail.php

的语法是:

布尔邮件(字符串$到,串$主题,串$ message [,string $ additional_headers [,string $ additional_parameters]])

  • 对于mail(),您使用的参数太多,应该只有四个参数。

为所有要发送的变量指定一个变量,并将其设置为“body”参数并使用手册中的标题。

即:

$to = "[email protected]"; 
$subject = "Mail form submitted"; 

$headers = 'From:'. $email . "\r\n"; // Sender's Email 
$headers .= 'Cc:'. $email . "\r\n"; // Carbon copy to Sender 

$body = " 

$course \n $firstname \n $surname \n $DOB \n $gender \n 
$address1 \n $address2 \n $city \n $postcode \n $mobile \n 
$home \n $email \n $residency \n $learning \n $qualifications 

"; 

if(mail($to, $subject, $body, $headers)){ 

    echo "Mail sent"; 
} 
else { 
    echo "Error, check your logs"; 
    // header("Location: apply.php"); exit; 
    // use echo OR header, not both and uncomment/comment out the one you want. 
} 

您的代码也是开放的SQL注入,用事先准备好的声明:

同时确保所有POST数组是正确的并保持价值。

错误报告会的帮助下,应该有你的PHP任何错误:

你可能头之前也可以输出。

要么删除echo并将其替换为标头,反之亦然;你不能同时使用两者。

如果您仍然无法发送邮件的问题,请咨询以下是问答&答:

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