2011-07-04 118 views
2

我试图让从URL XML内容:当我写出来的响应内容获取网络内容

HttpClient client = new DefaultHttpClient(); 
HttpGet request = new HttpGet(); 
request.setURI(new URI("http://www.domain.com/test.aspx")); 
HttpResponse response = client.execute(request); 
in = response.getEntity().getContent(); 

,这是内容结束前被截断。

有什么想法?

回答

1

您是否使用InputStreamReader作为输入流in

String s = ""; 
String line = ""; 
BufferedReader rd = new BufferedReader(new InputStreamReader(in)); 
try { 
    while ((line = rd.readLine()) != null) { s += line; } 
} catch (IOException e) { 
    // Handle error 
} 

// s should be the complete string 
+0

我将输入流传递给DocumentBuilder类的解析方法。 – alfdev

0

也许我已经解决了,是android模拟器。只需重新启动它一切正常。

感谢所有