2014-09-28 47 views
0
<?php 
    include('db_connect.php'); 

    $id = $_GET["id"]; 

    if(isset($_POST['name'])) 
    { 
     $name=mysql_real_escape_string($_POST['name']); 
     $query=mysql_query("SELECT * FROM brands WHERE name = '$name'",$link); 
     $row = mysql_num_rows($query); 

    if($row==0) 
    { 
     echo 
     " 
     <script type='text/javascript'> 
      $('#logo').animate({marginLeft:'20px'},100); 
      $('#logo').animate({marginLeft:'0px'},100); 
     </script> 
     "; 
    } 
    else 
    { 
     $database = mysql_query("SELECT * FROM brands",$link); 
     $logo = $_POST['name']; 
     $logo_n = $row["name"]; 

     if ($logo == $logo_n || $logo == strtolower($logo_n) || $logo == strtoupper($logo_n)) { 

      mysql_query("UPDATE brands SET level_br = '$id' WHERE id = $id",$link); 
     } 
     else { 
      echo "<script>alert('NO');</script>"; 
      echo "<script>console.log('NO');</script>"; 
     } 
    } 
    } 
?> 
+0

以及究竟是你的问题的出租车司机? – 2014-09-28 11:35:31

+2

看起来你要求我们给你写一篇关于Ajax *教程的简介。已经有很多了。试试Google。 – Quentin 2014-09-28 11:36:28

+0

我使用ajax,但更新数据库通过重新加载页面 – 2014-09-28 11:38:03

回答

0

阿贾克斯将允许您通过JavaScript使用PHP脚本,而无需重新加载页面

让说,你有3个文件:

的application.js

$(document).ready(function(){ 
     // add the click event to the checkbox 
     $('#TheCheckbox').click(function() { 

      // Looking if your checkox is checked 
      var Am_I_Checked = !$(this).is(':checked') 

      // Use javascrip to send an ajax call to your php file 
      var remoteFile = 'www.yourdomain.com/db_update.php'; 

      // Data to send to your php file, The php file will see 
      // those vas in the $_GET array ... 
      // This is json format use all the time in javascript if you need more info 
      // google it :) . 
      // http://www.w3schools.com/json/json_intro.asp 
      var dataToSend = { 
       'Am_I_Checked' : Am_I_Checked, 
       'variable1' : 'the value', 
       'variable2' : 'the value' 
       // etc... 
      } 

      // This is the fonction that will be executed once the php call is done 
      // I know its look like a variable, but its a lamba style function, that 
      // also exist in php is you dont know 
      // 
      // If you notice, the data parameter is what will be return by php (echoed by ...) 
      // In this example that will be recognize as json 
      var oneAjaxIsDone = function(data) { 
       //example 
       alert(data.whatever); // in this example, that will alert the string : "you want to return" 
      } 

      $.ajax({ 
       dataType: "json", 
       url: remoteFile, /* the remote script to call */ 
       data: dataToSend, /* the json data of element that you want to send to your script */ 
       success: oneAjaxIsDone /* there you pass your lamba */ 
       }); 

     }) 
    }) 

的index.html

<html> 
     <header> 
      <script src="jquery.js"> 
      <script src="application.js"> 
     </header> 
     <body> 
      <input id="TheCheckbox" type="checkbox"> 
     </body> 
    </html> 

db_update.php

<?php 
     $ajaxVars = $_GET[]; 

     // Do your database stuff ..... 

     // Now we will build the return, remeber the ajaxIsDone function above... 
     $return = array('whatever' => 'you want to return'); 

     // When you send data from javascript to php via ajax that was in json format 
     // we have to do the sameting here 
     $jsonString = json_encode($return); 

     echo $jsonString; 
    ?> 

重申不要问你,如果你使用AJAX或PHP的,因为他们没有做同样的工作

PHP:更新数据库,回报回答

html:containe you html and layout

javascrip PT:冰事件的复选框对象,并触发AJAX

AJAX:对于知道刚才把它看作你的颈部和你的服务器脚本

+0

非常感谢你我会尝试 – 2014-09-28 12:25:32

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