初始化阵列的与硬编码和生成的值

Question

此代码，其初始化与两个硬编码值的阵列的组合工作完全正常：

var db = new GoogleGraph { 
    cols = new ColInfo[] { 
     new ColInfo { id = "", label = "Date", pattern ="", type = "string" }, 
     new ColInfo { id = "", label = "Attendees", pattern ="", type = "number" }      
    }.ToList(), 
    rows = new List<DataPointSet>() 
}; 
db.cols.AddRange(listOfValues.Select(p => new ColInfo { id = "", label = p, type = "number" })); 

此代码，它试图增加一些动态生成的值不工作：

var db = new GoogleGraph { 
    cols = new ColInfo[] { 
     new ColInfo { id = "", label = "Date", pattern ="", type = "string" }, 
     new ColInfo { id = "", label = "Attendees", pattern ="", type = "number" }, 
     listOfValues.Select(p => new ColInfo { id = "", label = p, type = "number" })      
    }.ToList(), 
    rows = new List<DataPointSet>() 
}; 

我该如何正确实现上面的代码片段？

Answer 1

您不能将IEnumerable<T>传递给T[]这样的初始化程序。

你可以做你想做的通过将在自己的收藏硬编码的对象，然后连接动态的：

var db = new GoogleGraph { 
    cols = 
     new ColInfo[] { 
      new ColInfo { id = "", label = "Date", pattern ="", type = "string" }, 
      new ColInfo { id = "", label = "Attendees", pattern ="", type = "number" } 
     } 
     .Concat(listOfValues.Select(p => 
      new ColInfo { id = "", label = p, type = "number" }))      
     .ToList(), 
    rows = new List<DataPointSet>() 
};