Ç - 如果其他scanf函数无法正常运行

Question

我是新来的一般编码，并且很新的C.

我想用C编写一个程序，要求用户输入的和基于用户输入，打印特定文本到.txt文件。请看看我的代码，并让我知道我做错了什么。

请看看我的代码如下。非常感谢您的帮助。

马特

#include <stdio.h> 
#include <stdlib.h> 
#include <string.h> 


FILE * fptr; 

int main(){ 

char name[32]; 
char partNum[32]; 
char desc[250]; 
char ans1; 
char ans2; 
char sn[50]; 
char ansRep; 

fptr = fopen("C:\\Users\\mgreene\\Documents\\EmailTemplates\\QCIssue.txt", "w"); 

if (fptr ==0) 
{ 
printf("Error--file could not be opened\n"); 
exit(1); 
} 

printf("What is the customer's first name?\n"); 
scanf("%s", name); 

printf("With which Part number is the user experiencing difficulties?\n"); 
printf("Enter Part Number:"); 
scanf("%s", partNum); 

printf("Please enter a brief description of the problem\n"); 
scanf("\n%s", desc); 

printf("Does the product have a serial number?\n"); 
scanf("%c", &ans1); 

if (!strcmp(&ans1, "y")== 0) 
{ 
printf ("Do you know the serial number?\n"); 
scanf("\n%c", &ans2); 

if (!strcmp(&ans2, "y")==0) 
{ 
printf ("Please enter the SN:\n"); 
scanf("\n%s", sn); 

fprintf(fptr, "\nHi %s,\n\nI hope this message finds you well.\n\nI write to you today  as the Quality Manager at Blank. I received a report that you're experiencing difficulties with part: %s, %s; specifically, the report indicates that %s. Is that an accurate description of the problem? Firstly please accept my apologies on behalf of Blank for the difficulties you're experiencing with this part. As an ISO9001:2008 compliant organization, Blank takes all issues related to customer satisfaction very seriously. It is our intention to resolve this matter as soon as is possible.\n\n", name, partNum, sn, desc); 
    } 
    else 
    { 
    fprintf(fptr, "\nHi %s,\n\nI hope this message finds you well.\n\nI write to you today as the Quality Manager at Blank. I received a report that you're experiencing difficulties with part: %s; specifically, the report indicates that %s. Is that an accurate description of the problem? Firstly please accept my apologies on behalf of Blank for the difficulties you're experiencing with this part. As an ISO9001:2008 compliant organization, Blank takes all issues related to customer satisfaction very seriously. It is our intention to resolve this matter as soon as is possible.\n\nBefore I can begin an investigation into this problem, I'll need the serial number from that unit. Can you please forward me the serial number as soon as you're able? Once I have that, I can begin the investigation on our end. Thanks.\n\n", name, partNum, desc); 
    } 
} 
else if (strcmp(&ans2, "y")==0) 
{ 
printf("Will Blank be sending the customer a replacement? Please enter y or n\n"); 
scanf("\n%c", &ansRep); 

     if (!strcmp(&ansRep, "y")==0) 
     { 
      fprintf(fptr, "Blank can send you a replacement product as soon as is possible. In order to ensure that the replacements are shipped to the correct address, will you please confirm you shipping address via email? Thanks.\n\n"); 
      fprintf(fptr, "Thank you for your assistance in resolving this matter. Please let us know if you have any additional questions, comments, or concerns about this specific issue or any issues related to products distributed by Blank.\n\n"); 
fprintf(fptr, "Have a great day!"); 
     } 
     else 
     { 
      fprintf(fptr, "Thank you for your assistance in resolving this matter. Please let us know if you have any additional questions, comments, or concerns about this specific issue or any issues related to products distributed by Blank.\n\nHave a great day!"); 
     } 
} 
fclose (fptr); 
return (0); 
} 

Answer 1

首先第一件事情：ANS1和ANS2是炭灰;你正在做strcmp（& ans2，“y”） - 在这里，“y”是一个字符串（由NULL结尾的字符数组），因为它用双引号引起来。别的之前，您应该更换的东西这些变量的所有比较喜欢

if(ans1 == 'y') 

此外，当你万一看你应该在％C的前面添加一个空格字符存在一些空白或偏离之前输入的新行 - scanf（“％c”，& ans1）;

Answer 2

卸下在scanf("\n%s" [...]\n和scanf("%c"和scanf("\n%c"（除去\n）加入%c之前的空间中可能会有帮助。

Answer 3

if (!strcmp(&ans1, "y")== 0)是错误的，可能会修改为if(ans1 != 'y')。您应该在代码中对if (!strcmp(&ans2, "y")==0)，if (strcmp(&ans2, "y")==0)，if (!strcmp(&ansRep, "y")==0)进行类似的修改。

而对于scanf("%c", &ans1);，你可以按照如下改写：

scanf(" %c", &ans1); 

Answer 4

你可以创建一个简单的函数从scanf

void clear_input_buffer(void) 
{ 
    char buffer[100]; 
    fgets(buffer, 100, stdin); 
} 

捉流浪狗则包括它scanf

scanf("%s", name); 
clear_input_buffer(); 

后

Answer 5

简答：我觉得你的st戒指包含垃圾！

C中的字符串必须以空字节（'\ 0'）结尾。当您在堆栈（或堆）上创建char数组时，该数组的内容可能会充满您当时存储的任何垃圾。试着运行这个小程序来看看我的意思。有人可能预测这个程序会打印3个空白行，但它应该打印3行随机垃圾（每次运行这个程序时垃圾都应该不同）。

#include <stdio.h> 

int main(){ 

char name[32]; 
char partNum[32]; 
char desc[250]; 

printf("%s\n", name); 
printf("%s\n", partNum); 
printf("%s\n", desc); 

} 

有可以改进程序中的几件事情你已经发布，但具体解决您的包含字符串的垃圾，这里是一个简单的解决方案：

更换喜欢char name[32];线char *name = calloc(32, sizeof char);并确保在程序结束时释放这些内存分配，如free(name)。

calloc将它分配的所有内存设置为NULL，这样您的字符串将不再包含垃圾。

如果您在输出文件中遇到垃圾，应该这样做。

还要注意

您正在使用固定大小的字符数组。如果用户决定输入比预期更长的内容，会发生什么情况？输入将流入内存的其他部分，并可能影响其他变量的值。