项目不附加到列表，或列表返回为空python？

Question

在我的代码中，项目百分比不添加到for循环的每次迭代中的列表lnpercentgrade，但我不知道为什么。当我尝试在lnpercentgrade（代码结尾）中汇总项目时，我返回0，因为lnpercentgrade是empy。 我将lnpercentgrades声明为maininput（）函数之外的全局变量，因为否则在代码底部时，当我尝试求和（lnpercentgrades）时，我返回“lnpercentgrades not defined”。

我猜在maininput（）函数内部不会修改lnpercentgrades，尽管我确信我在.append函数之前正确地输入了它。

什么我真的想做的是与100相匹配的总和（lnpercentgrades），但是当我进入5个项目全部为20的值，总和为0，而不是100

重要线路都标用箭头< < < < < < < < < < < < < < < < < < < < <

lnpercentgrades = [] <<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<<< 
def maininput(): 
    numtests = int(input("Enter # of tests:")) 
    numassign = int(input("Enter # of assignments:")) 
    numquizzes = int(input("Enter # of quizzes:")) 
    numlabs = int(input("Enter # of labs:")) 

    l = [numtests, numassign, numquizzes, numlabs] 
    ln = ["test", "assignments", "quizzes", "labs"] 
    lnpercentgrades = [] <<<<<<<<<<<<<<<<<<<<<<<<<<<<<<< 
    testwavg = None 
    numassignwavg = None 
    numquizzeswavg = None 
    numlabswavg = None 
    numfinalwavg = None 

    lnwavg = [testwavg, numassignwavg, numquizzeswavg, numlabswavg] 
    print(l[0]) 
    print("Is there a separately weighted final?") 
    yn = int(input("Enter 1 for yes. 2 for no:")) 
    while (yn > 2 or yn < 1): 
     yn = int(input("Enter 1 for yes. 2 for no, please:")) 

    n = 4 
    if yn == 1: 
     final = 1 
     l.append(final) 
     ln.append("final") 
     lnwavg.append(numfinalwavg) 
     n = 5 


    for i in range (n): 
     if l[i] > 0: 
      print("Enter % of total grade of",ln[i],":") 
      percentgrade = float(input("")) 
      print("you inputed:", percentgrade) 
      lnpercentgrades.append(percentgrade) <<<<<<<<<<<<<<<<<<<<<< 
      percentgrade = percentgrade*.01 


      varscoreslist = [] 
      for x in range(l[i]): 
       print("Enter score of", ln[i], x+1,"as a fraction:") 
       from fractions import Fraction 
       inputfrac = input("") 
       varscore = float(sum(Fraction(s) for s in inputfrac.split())) 
       #the above converts fractional inputs to decimals 
       varscoreslist.append(varscore) 

      if ln[i] == "labs": 
       score = sum(varscoreslist) 
      else: 
       sumscores = sum(varscoreslist) 
       score = sumscores/l[i] 

      lnwavg[i] = score*percentgrade 

maininput() 
print(lnpercentgrades) 
print("sum of percent of grades", sum(lnpercentgrades)) <<<<<<<<<<<<<<< 

if float(sum(lnpercentgrades)) != 100: <<<<<<<<<<<<<<<<<<<<<<<<<<<<<< 
    print("Sorry, the grade percent of each item enter did not sum to 100:") 
    print("Program will rerun.") 
    input("") 
    maininput() 

coursegrade = sum(lnwavg) 
print("Your course grade is:", coursegrade) 

input("") 

Answer 1

乍一看，它看起来像你可能有一个范围界定问题。您正在修改函数内部的列表，但请记住这是列表的本地副本。尽管你在外部范围声明它，但你并没有用global来表示它，这意味着它会创建一个函数本地副本，完成它的业务然后退出，而不会影响'main'列表。

我会建议修改你的函数来返回你想要的列表，以便你可以像预期的那样使用它们。这是一个基本的例子：

def MyFunc(): 
    l1 = ['my', 'first', 'list'] 
    l2 = ['another', 'list'] 
    return l1, l2 

main_list, second_list = MyFunc() 

print(main_list) 
print(second_list) 

将输出：

['my', 'first', 'list'] 
['another', 'list'] 

如果你真的想保持变量外的范围，你将有global到序言它的函数内（我可能会用第一种方法去虽然）：

main_list = [] 
second_list = [] 

def MyFunc(): 
    global main_list 
    global second_list 
    main_list = ['more', 'good', 'stuff'] 
    second_list = ['another', 'list'] 


MyFunc() 

print(main_list) # ['more', 'good', 'stuff'] 
print(second_list) # ['another', 'list']