2013-10-03 35 views
0

我正在使用毕加索在我的Android应用程序中设置gridview。我想要做的是基本上在gridview中按下图像并转到详细视图。Android Picasso GridView - 将URL数据存储在Integer数组中?

的数据字符串数组被填充,像这样:

static final String[] URLS = { 
    "http://i.imgur.com/file1.jpg", "http://i.imgur.com/file2.jpg", 
    "http://i.imgur.com/file3.jpg", "http://i.imgur.com/file4.jpg" 
}; 

ImageAdapter这些网址将被放在一个字符串的ArrayList:

public class ImageAdapter extends BaseAdapter { 
    private final Context context; 
    private final List<String> urls = new ArrayList<String>(); 

    public ImageAdapter(Context context) { 
    this.context = context; 

    // Ensure we get a different ordering of images on each run. 
    Collections.addAll(urls, Data.URLS); 
    //Collections.shuffle(urls); 

    // Triple up the list. 
    ArrayList<String> copy = new ArrayList<String>(urls); 
    urls.addAll(copy); 
    } 

    @Override public View getView(int position, View convertView, ViewGroup parent) { 
    SquaredImageView view = (SquaredImageView) convertView; 
    if (view == null) { 
     view = new SquaredImageView(context); 
     view.setScaleType(CENTER_CROP); 
    } 

    // Get the image URL for the current position. 
    String url = getItem(position); 

    // Trigger the download of the URL asynchronously into the image view. 
    Picasso.with(context) // 
     .load(url) // 
     .placeholder(R.drawable.placeholder) // 
     .error(R.drawable.error) // 
     .fit() 
     .centerCrop()// 
     .into(view); 

    return view; 
    } 

    @Override public int getCount() { 
    return urls.size(); 
    } 

    @Override public String getItem(int position) { 
    return urls.get(position); 
    } 

    @Override public long getItemId(int position) { 
    return position; 
    } 

} 

问题是,当我想该项目的ID,它都存储在字符串中。这里是我的详细信息查看活动的样子:

public void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
    setContentView(R.layout.full_image); 

    // get intent data 
    Intent i = getIntent(); 

    // Selected image id 
    int position = i.getExtras().getInt("id"); 
    ImageAdapter ia = new ImageAdapter(this); 

    ImageView iv = (ImageView) findViewById(R.id.full_image_view); 
    iv.setImageResource(ia.getItemId(position)); 
} 

position是从我的主要活动,它是整数。当我想把getItemId,setImageResource引发此错误:

The method setImageResource(int) in the type ImageView is not applicable for the arguments (long)

你们是否有任何想法如何解决这一问题?

编辑:新增ImageAdapter类代码

+0

尝试'iv.setImageResource(网址[位置]);'也发表您的'ImageAdapter' – VenomVendor

+0

u能显示你的ImageAdapter类代码? –

+0

在问题中添加 – AimanB

回答

2

你仍然需要调用毕加索在详细信息视图,从适配器,而不是ID通过URL。

Picasso.with(context) // 
    .load(ia.getItem(position)) // 
    .placeholder(R.drawable.placeholder) // 
    .error(R.drawable.error) // 
    .fit() 
    .centerCrop()// 
    .into(iv);