我有一个表从一个查询echo'd到我们的数据库中的表,我得到它回显出下表;排序表中的行数据PHP?
http://www.skulldogs.com/dev/testview.php
我希望它在正确的绿色行 “黄” 行里的 “mainToon” 的名称,例如匹配排序:
高voltege
--REAL MCCOY
--Cpt挂钩
riazall
- Valeside
我的代码回显上述页面;
<?php
$result = mysql_query("SELECT * FROM `members`");
echo "<table border='1'>
<tr>
<th>Character ID</th>
<th>Name</th>
<th>MainToon</th>
<th>toonCategory</th>
</tr>";
while ($row = mysql_fetch_array($result)) {
$characterID = $row['characterID'];
$name = $row['name'];
$startDateTime = $row['startDateTime'];
$logonDateTime = $row['logonDateTime'];
$logoffDateTime = $row['logoffDateTime'];
$location = $row['location'];
$role = $row['role'];
$vouchedBy = $row['vouchedBy'];
$positionHeld = $row['positionHeld'];
$remarks = $row['remarks'];
$afkNotice = $row['afkNotice'];
$toonCategory = $row['toonCategory'];
$mainToon = $row['mainToon'];
$watch = $row['watch'];
if ($toonCategory == 'Main Toon') {
echo "<tr bgcolor='#00FF00'>"; }
else {
echo "<tr bgcolor='#FFFF00'>"; }
echo "<td>" . $characterID . "</td>";
echo "<td>" . $name . "</td>";
echo "<td>" . $mainToon . "</td>";
echo "<td>" . $toonCategory . "</td>";
echo "</tr>";
}
echo "</table>";
?>
此刻我不回应其他数据,直到我可以找出如何显示相应的表。可以这样做吗?
这是我如何显示表;
http://www.skulldogs.com/dev/mockup.php
它只在表格视图中按“类别”对它们进行排序,而不是将其与可以在“mainToon”回显中找到的“ALT”(第二个!)连接起来。 – 2013-02-26 00:07:17
@StephenJackson我有2个可能的新答案 - 希望有人会为你工作。 – rjmunro 2013-02-26 00:31:16
感谢兄弟工作的一种享受! – 2013-02-26 00:40:12