如何订购此查询？

Question

DEMO SQL FIDDLE

我喜欢在上面演示了查询，但我不知道如何订购此查询，我希望得到的结果是这样的：

Name 
----- 
Menu_1 
------- 
..... Sub_Menu_1 
------- 
Menu_2 
------- 
..... Sub_Menu_2 
------- 
..........Sub_Sub_Menu_2 
------- 
Menu_3 
------- 

我该怎么办这个？感谢

编辑（从SQLFiddle演示资讯）

表：

CREATE TABLE Menus 
    (
    IdMenu int primary key, 
    IdParentMenu varchar(20), 
    Name varchar(30) 
    ); 

数据：

INSERT INTO Menus 
(IdMenu, IdParentMenu, Name) 
VALUES 
('1', '0', 'Menu_1'), 
('2', '0', 'Menu_2'), 
('3', '0', 'Menu_3'), 
('4', '1', 'SubMenu_1'), 
('5', '2', 'SubMenu_2'), 
('6', '5', 'Sub-SubMenu_2'); 

我的查询：

WITH MenuCTE (IdMenu, IdParentMenu, ParentMenu, Name, Lvl) 
AS 
(
    -- Anchor member 
    SELECT m.IdMenu, m.IdParentMenu, CAST('' AS varchar) AS ParentMenu, m.Name, 0 AS Lvl 
    FROM dbo.Menus AS m 
    WHERE CAST(m.IdParentMenu AS INT) = 0 
    UNION ALL 

    -- Recursive member 
    SELECT m.IdMenu, m.IdParentMenu, CAST(mc.Name AS varchar) AS ParentMenu, m.Name, Lvl + 1 AS Lvl 
    FROM dbo.Menus AS m 
    INNER JOIN MenuCTE AS mc 
     ON CAST(m.IdParentMenu AS INT) = mc.IdMenu 
) 
SELECT IdMenu, IdParentMenu, ParentMenu, REPLICATE('....', Lvl) + Name 
FROM MenuCTE 
--WHERE Lvl > 0 
ORDER BY IdParentMenu 
GO 

Answer 1

添加，通过本场计算路径和秩序领域：

WITH MenuCTE (IdMenu, IdParentMenu, ParentMenu, Path, Name, Lvl) 
AS 
(
    -- Anchor member 
    SELECT m.IdMenu, m.IdParentMenu, 
      CAST('' AS varchar) AS ParentMenu, 
      CAST(m.Name AS varchar) AS Path, 
      m.Name AS Name, 
      0 AS Lvl 
    FROM dbo.Menus AS m 
    WHERE CAST(m.IdParentMenu AS INT) = 0 
    UNION ALL 

    -- Recursive member 
    SELECT m.IdMenu, m.IdParentMenu, 
      CAST(mc.Name AS varchar) AS ParentMenu, 
      CAST(mc.Path + '.'+ m.Name AS varchar) AS Path, 
      m.Name, 
      Lvl + 1 AS Lvl 
    FROM dbo.Menus AS m 
    INNER JOIN MenuCTE AS mc 
     ON CAST(m.IdParentMenu AS INT) = mc.IdMenu 
) 
SELECT IdMenu, IdParentMenu, ParentMenu, 
     REPLICATE('....', Lvl) + Name, Path 
FROM MenuCTE 
ORDER BY Path 

注：在上面的查询Path使用Name场而建，因此订货菜单，子菜单等是根据他们的名字进行的。 Path值是这样的：

Menu_1 
Menu_1.SubMenu_1 
Menu_2 
Menu_2.SubMenu_2 
Menu_2.SubMenu_2.Sub-SubMenu_2 

如果您想通过IDS订购，然后代替Name使用IdMenu只是内置Path。在这种情况下Path值将是这样的：

1 
1.4 
2 
2.5 
2.5.6 

Demo here

Answer 2

这应该是不错的。

WITH MenuCTE (IdMenu, IdParentMenu, ParentMenu, Ord, Name, Lvl) 
AS 
(
    -- Anchor member 
    SELECT m.IdMenu, m.IdParentMenu, CAST('' AS varchar) AS ParentMenu, CAST(m.IdMenu AS varchar) as Ord, m.Name, 0 AS Lvl 
    FROM dbo.Menus AS m 
    WHERE CAST(m.IdParentMenu AS INT) = 0 
    UNION ALL 

    -- Recursive member 
    SELECT m.IdMenu, m.IdParentMenu, CAST(mc.Name AS varchar) AS ParentMenu, cast((mc.Ord + CAST(m.IdMenu AS varchar)) as varchar) as Ord, m.Name, Lvl + 1 AS Lvl 
    FROM dbo.Menus AS m 
    INNER JOIN MenuCTE AS mc 
     ON CAST(m.IdParentMenu AS INT) = mc.IdMenu 
) 
SELECT ord, IdMenu, IdParentMenu, ParentMenu, REPLICATE('....', Lvl) + Name 
FROM MenuCTE 
--WHERE Lvl > 0 
ORDER BY ord 
GO