下面的代码是在我的应用程序服务器代码:的Java停止服务器线程
private int serverPort;
private Thread serverThread = null;
public void networkListen(int port){
serverPort = port;
if (serverThread == null){
Runnable serverRunnable = new ServerRunnable();
serverThread = new Thread(serverRunnable);
serverThread.start();
} else {
}
}
public class ServerRunnable implements Runnable {
public void run(){
try {
//networkConnected = false;
//netMessage = "Listening for Connection";
//networkMessage = new NetworkMessage(networkConnected, netMessage);
//setChanged();
//notifyObservers(networkMessage);
ServerSocket serverSocket = new ServerSocket(serverPort, backlog);
commSocket = serverSocket.accept();
serverSocket.close();
serverSocket = null;
//networkConnected = true;
//netMessage = "Connected: " + commSocket.getInetAddress().getHostAddress() + ":" +
//commSocket.getPort();
//networkMessage = new NetworkMessage(networkConnected, netMessage);
//setChanged();
//notifyObservers(networkMessage);
} catch (IOException e){
//networkConnected = false;
//netMessage = "ServerRunnable Network Unavailable";
//System.out.println(e.getMessage());
//networkMessage = new NetworkMessage(networkConnected, netMessage);
//setChanged();
//notifyObservers(networkMessage);
}
}
}
代码排序的工作,即如果IM尝试一条直线连接两端的交流和更新。
问题是,即时通讯侦听连接,如果我想退出监听然后服务器线程继续运行,并导致问题。
我知道我不应该在一个线程上使用.stop(),所以我想知道在解决这个问题时应该看起来像什么?
编辑:注释掉不需要的代码。
非常感谢你“从循环中解脱” - 这是关键! – Kirzilla 2011-11-02 21:23:19