MySQL选择具有相同列值的行

Question

我需要从下表中获取具有相同列值的行，我尝试了以下方法，但它只给出了单行。

select * 
from employee e 
group by e.empsalary 
having count(e.empsalary) > 1 

表员工

请给我建议的方法。

Answer 1

您应该能够通过加入表本身来实现：

SELECT 
    a.* 
FROM 
    employee a 
    JOIN employee b 
     ON a.empsalary = b.empsalary 
     AND a.empid != b.empid 

Answer 2

使用一个内连接来加入你的查询发布。

select A.* from employee A 
inner join (
    select empsalary 
    from employee 
    group by empsalary 
    having count(*) > 1 
) B ON A.empsalary = B.empsalary 

Answer 3

像这样的事情也许

SELECT * FROM employee a 
WHERE EXISTS (
    SELECT 1 FROM employee b 
    WHERE a.empsalary = b.empsalary 
    AND a.empid <> b.empid 
); 

演示 - 只要你想http://sqlfiddle.com/#!2/d75d9/4

Answer 4

select * from employee where empsalary IN(select empsalary from employee group by empsalary having count(empsalary) > 1) 

尝试This.It给2行。

演示： http://sqlfiddle.com/#!2/d75d9/6