2012-06-21 61 views
4
select p.partnerid, 
sum(case when c.amount is not null then c.amount else 0 end) as amount, 
sum(case when c.netamt is not null then c.netamt else 0 end) as total, 
sum(case when (c.netamt - d.paidamount) is not null then (c.netamt - d.paidamount) else 0 end) as remainingamount, 
sum(case when d.paidamount is not null then d.paidamount else 0 end) as paidamt 
from customerinfo c 
left join dailypayments d on c.accno = d.accno 
right join partnerinfo p on c.partnerid = p.partnerid 
where (d.paiddate is null or (d.paiddate >= '2011-3-15' and d.paiddate <= '2012-6-13')) and p.manager = 7 group by p.partnerid 

从athe上面的查询我需要从两个表中减去两个表中第二个表中没有值的值。当空值存在时从两个表中减去两个值

为更好地理解看下面的图像。

pic http://i46.tinypic.com/w1zkp4.jpg

+0

该字段为空? – Sebas

回答

9

使用IFNULL()功能删除case和简化计算:

sum(c.netamt - ifnull(d.paidamount, 0)) as remainingamount,