我上传图像和使用PHP在Mysql数据库中保存记录时遇到问题,有人能帮助我吗?如何使用PHP在Mysql数据库中上传图像
代码:
<?php
ini_set('mysql.connect_timeout', 300);
ini_set('default_socket_timeout', 300);
?>
<html>
<body>
<form method="post" enctype="multipart/form-data">
</br>
<input type="text" name="dbname"/>
<input type="file" name="dbimage"/>
<br> <br>
<input type="submit" name"submit" value"Upload"/>
</form>
<?php
if(isset($_POST['submit'])){
if(getimage($_FILES['dbimage']['tmp_name']) == FALSE) {
echo "Please select an image";
} else {
$dbimage = addcslashes($_FILES['dbimage']['tmp_name']);
$dbname = addcslashes($_FILES['dbimage']['dbname']);
$dbimage = file_get_contents($image);
$dbimage = base64_encode($dbimage);
saveimage($dbname, $dbimage);
}
function saveimage() {
$con = mysql_connect("localhost", "root", "");
mysql_select_db("db_test", $con);
$qry = "insert into table1 (dname,dpic) values ('$dbname','$dbimage')";
$result = mysql_query($qry, $con);
if ($result){
echo "Image uploaded.";
} else {
echo " Image not uploaded.";
}
}
}?>
</body>
</html>
你的“麻烦”是什么?什么不起作用?你得到什么错误? (你打开了错误报告吗?) – Epodax
没有错误,但记录不保存 –
然后你很可能没有打开错误报告,打开错误报告(把它放在你的代码的顶部:'error_reporting( E_ALL); ini_set(“display_errors”,1);'),看看它说什么。 – Epodax