2011-07-17 31 views
1

我尝试了许多变化,但没有运气。我可以NSLog阵列,我得到这个:从NSArray设置UITextField

2011-07-17 00:54:54.886 Widgets[13444:207] <Widget: 0x5e2aad0> (entity: Widget; id: 0x5e0d8e0 <x-coredata://E64A0BCE-2344-4EE1-89CC-164ACD8995D6/Recipe/p115> ; data: { 
    success = 1; 
    coconutscarried = nil; 
    name = "African Swallow"; 
    uidnumber = "105 "; 
}) 

我怎样才能简单地设置文本字段?

对不起,但这是我试过的(杂乱)代码的分类。数组和文本字段已经以.h/m为单位设置并绑定到IB

- (void)viewDidLoad { 
    [super viewDidLoad]; 
    //NSLog(@"%@",[[swallowArray name] text]); // doesnt work 
    //NSLog(@"The string at index is %@.", [self.swallowArray objectAtIndex:0]);//nope... 
    for (int i = 0; i < [swallowArray count]; i++) { 
     //nameTextField.text = [[swallowArray objectAtIndex:i] uidnumber]; 
     //NSLog(@"%@",swallowArray.name); 
    //} 
    //nameTextField.text = [[swallowArray objectAtIndex:0] uidnumber]; 
    //NSString* strRate = [[swallowArray object] uidnumber]; 
    nameTextField.text = [nameTextField.text stringByAppendingString:[NSString localizedStringWithFormat:@", %@", [[swallowArray objectAtIndex:i] name]]]; 

} 

以及更多。这已经很简单,但我是一个noob。

谢谢!

回答

0

5小时搜索后,我张贴在这里,并找到答案字面上5分钟!

NSString *nameFromArray = [NSString stringWithFormat:@"%@", [eventArray valueForKey:@"name"]]; 
NSLog(@"%@", nameFromArray); 

希望这可以帮助别人!