PHP连接两个MySQL表中的结果

Question

我有插入注释数据和评论数据这样的两个MySQL表：

评论：

|id|post_id|text|name|timestamp|approved|parent_id|type|ip| 

评论：

在行动我

|id|postID|comments_id|reviewfield1|reviewfield2|reviewfield3 

为每条评论插入一条评论。现在，我需要证明与评论name /打印评论列表和text + reviewfield1reviewfield2reviewfield3对于那些评论是approved这样每个评论：

commenter 1 
    text 
    reviewfield1 
    reviewfield2 
    reviewfield3 

TRY：

"SELECT name,text,timestamp FROM " . COMMENTS . " LEFT JOIN " . REVIEWS . " WHERE " . COMMENTS . ".id = " . REVIEWS . ".comments_id AND 
     post_id = ? AND type = ? AND approved = 1 ", $id, $type" 

但这不是工作我。如何使用PHP JOIN方法生成这个？

Answer 1

您在查询中犯了错误。它必须是这样的：

"SELECT name,text,timestamp,reviewfield1 FROM " . COMMENTS . " LEFT JOIN " . REVIEWS . " ON " . COMMENTS . ".id = " . REVIEWS . ".comments_id WHERE 
     post_id = ? AND type = ? AND approved = 1 ", $id, $type" 

并且您可以从第二个（连接）表中选择行，与第一个表相同。