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Question

我有两个型号

class Business(Basetable): 
name = models.CharField(max_length=120) 
slug = models.SlugField(max_length=150) 
logo=models.OneToOneField("BusinessLogo",null=True,on_delete=models.SET_NULL) 


class Address(models.Model): 
business = models.ForeignKey("Business", related_name='biz_address') 
address1 = models.CharField(max_length=100,null=True) 
address2 = models.CharField(max_length=100,null=True) 
state = models.ForeignKey(States,null=True,on_delete=models.SET_NULL) 
city = models.ForeignKey(City,null=True,on_delete=models.SET_NULL) 

view.py

class BusinessResource(ModelResource): 
class Meta: 
    queryset = Business.objects.filter(status='P').order_by('-id') 
    resource_name = 'business' 
    filtering = { 
     'is_black_business': ALL,   
     'city': ALL_WITH_RELATIONS, 

    } 
def dehydrate(self,bundle): 
if buss_address.city:bundle.data['city'] = buss_address.city.name 
     else:bundle.data['city'] = '' 
    // i am getting city here 

问题是我需要使用城市..我怎么能做到这一点来筛选公司吗？任何猜测

Answer 1

class BusinessResource(ModelResource): 
    addresses = fields.ToManyField(AddressResource, 'biz_address') 
    class Meta: 
     filtering = { 
        'addresses': ALL_WITH_RELATIONS, 
       } 

class AddressResource(ModelResource): 
    city = fields.ToOneField(CityResource, 'city') 
    class Meta: 
     filtering = { 
        'city': ALL_WITH_RELATIONS, 
        } 

第二种方法是通过覆盖build_filters和apply_filters方法来编写自定义过滤器。