Oracle SQL中的聚合

Question

我需要一些关于Oracle SQL中聚合问题的帮助。我希望这不是太简单，但我真的不知道该怎么做。

我有以下栏目：

Customer_ID (int) 
Countract_ID (int) 

• 每个合同可以包括几个不同的客户
• 每个客户可以包含在几个合同。

我需要添加一个新的列，其中包含每个成员（包括当前成员）的平均合同数量。例如：

ContractID |CustomerID | "AVG sum of contracs per member in the contract" 
123   | 11  |(3 + 2 + 1)/3 = 2 
123   | 22  |(3 + 2 + 1)/3 = 2 
123   | 33  |(3 + 2 + 1)/3 = 2 
321   | 11  |(3 + 2 + 2 + 1)/4 = 2 
321   | 55  |(3 + 2 + 2 + 1)/4 = 2 
321   | 22  |(3 + 2 + 2 + 1)/4 = 2 
321   | 88  |(3 + 2 + 2 + 1)/4 = 2 
987   | 11  |(3 + 2 + 1 + 1)/4 = 1.75 
987   | 55  |(3 + 2 + 1 + 1)/4 = 1.75 
987   | 99  |(3 + 2 + 1 + 1)/4 = 1.75 
987   | 77  |(3 + 2 + 1 + 1)/4 = 1.75 

有人知道什么是诸如聚合的查询吗？

Answer 1

下面是一种方法，我们使用了几个分析函数：count() over()和avg() over()。

-- sample of data 
with t1(Contractid ,Customerid) as(
    select 123 , 11 from dual union all 
    select 123 , 22 from dual union all 
    select 123 , 33 from dual union all 
    select 321 , 11 from dual union all 
    select 321 , 55 from dual union all 
    select 321 , 22 from dual union all 
    select 321 , 88 from dual union all 
    select 987 , 11 from dual union all 
    select 987 , 55 from dual union all 
    select 987 , 99 from dual union all 
    select 987 , 77 from dual 
) 
-- the query 
-- analytic functions cannot be nested, thus inline vew 
select contractid 
     , customerid 
     , avg(cnt) over(partition by contractid) as average 
    from (select contractid 
       , customerid  
       , count(contractid) over(partition by customerid) cnt 
      from t1) 
order by contractid, customerid 

结果：

CONTRACTID CUSTOMERID AVERAGE 
---------- ---------- ---------- 
     123   11   2 
     123   22   2 
     123   33   2 
     321   11   2 
     321   22   2 
     321   55   2 
     321   88   2 
     987   11  1.75 
     987   55  1.75 
     987   77  1.75 
     987   99  1.75 

11 rows selected 

Sqlfiddle demo