如何删除阵列的PHP的值

Question

请帮助 时，我想哟当我打印阵列之后从阵列布欧中删除一个元素它显示错误注意未定义偏移：3行号16

<?php 
    $value = 22; 
    $numbers = array(4, 6, 2, 22, 11); 
    $arrlength = count($numbers); 

    for($y = 0; $y < $arrlength ; $y++) { 
     if ($numbers[$y] == $value) { 
      unset($numbers[$y]); 
     } 
    } 
    $arrlength = count($numbers); 
    for($x = 0; $x < $arrlength; $x++) { 
     echo $numbers[$x]; 
     echo "<br>"; 
    } 
?> 

Answer 1

您应该使用“array_values（）”重新索引数组。你可以在这里找到解释：http://php.net/manual/en/language.types.array.php#language.types.array.useful-funcs

Answer 2

使用array_values()。

<?php 
$value = 22; 
$numbers = array(4, 6, 2, 22, 11); 
$arrlength = count($numbers); 

for($y = 0; $y < $arrlength ; $y++) { 
if ($numbers[$y] == $value) { 
    unset($numbers[$y]); 
} 
} 
$numbers = array_values($numbers); 
$arrlength = count($numbers); 
for($x = 0; $x < $arrlength; $x++) { 
echo $numbers[$x]; 
echo "<br>"; 
} 
?> 

检查在线演示：Click Here

OR

<?php 
$value = 22; 
$numbers = array(4, 6, 2, 22, 11); 
$arrlength = count($numbers); 

for($y = 0; $y < $arrlength ; $y++) { 
if ($numbers[$y] == $value) { 
    unset($numbers[$y]); 
} 
} 
//$numbers = array_values($numbers); 
//$arrlength = count($numbers); 
foreach($numbers as $key=>$num) { 
echo $num; 
echo "<br>"; 
} 
?> 

Answer 3

你要打印不存在关键

的元素试试这个：

<?php 
$value = 22; 
$numbers = array(4, 6, 2, 22, 11); 
$arrlength = count($numbers); 

for($y = 0; $y < $arrlength ; $y++) { 
    if ($numbers[$y] == $value) { 
     unset($numbers[$y]); 
    } 
} 
foreach($numbers as $k => $number) 
    echo "key: ". $k . " value: ". $number . "<br />";