我使用xtable
来自动生成LaTeX表格,并且想要在单元格中强制换行符/换行符。xtable单元格中的换行符
这可以在小区内使用\newline
来完成,但我无法阻止xtable
从$\backslash$
代我反斜杠(\
)。
这里有一个例子....
library(magrittr)
library(xtable)
my.data <- cbind(c("1", "2", "3"),
c("0", "1", "2"),
c("2", "3", "4")) %>%
as.data.frame()
## Generate output variable
my.data$out <- paste0(my.data$V1,
" \\newline (",
my.data$V2,
" to ",
my.data$V3,
")")
## Check the data frame...
my.data
V1 V2 V3 out
1 1 2 3 1 \\newline (2 to 3)
2 0 1 2 0 \\newline (1 to 2)
3 2 3 4 2 \\newline (3 to 4)
## Now generate xtable
xtable(my.data)
% latex table generated in R 3.2.0 by xtable 1.7-4 package
% Wed Jun 24 11:51:59 2015
\begin{table}[ht]
\centering
\begin{tabular}{rllll}
\hline
& V1 & V2 & V3 & out \\
\hline
1 & 1 & 2 & 3 & 1 $\backslash$newline (2 to 3) \\
2 & 0 & 1 & 2 & 0 $\backslash$newline (1 to 2) \\
3 & 2 & 3 & 4 & 2 $\backslash$newline (3 to 4) \\
\hline
\end{tabular}
\end{table}
的paste0()
工作正常预期,但通过这个数据帧xtable
没有什么我预期的结果(/希望),这是....
xtable(my.data)
% latex table generated in R 3.2.0 by xtable 1.7-4 package
% Wed Jun 24 11:51:59 2015
\begin{table}[ht]
\centering
\begin{tabular}{rllll}
\hline
& V1 & V2 & V3 & out \\
\hline
1 & 1 & 2 & 3 & 1 \newline (2 to 3) \\
2 & 0 & 1 & 2 & 0 \newline (1 to 2) \\
3 & 2 & 3 & 4 & 2 \newline (3 to 4) \\
\hline
\end{tabular}
\end{table}
因此,通过乳胶解析,当我在该单元格换行符。
类似的问题有关line breaks in captions建议使用双反斜线转义,但并不在这种情况下无论是工作...
my.data$out <- paste0(my.data$V1,
" \\\\newline (",
my.data$V2,
" to ",
my.data$V3,
")")
% latex table generated in R 3.2.0 by xtable 1.7-4 package
% Wed Jun 24 11:57:04 2015
\begin{table}[ht]
\centering
\begin{tabular}{rllll}
\hline
& V1 & V2 & V3 & out \\
\hline
1 & 1 & 2 & 3 & 1 $\backslash$$\backslash$newline (2 to 3) \\
2 & 0 & 1 & 2 & 0 $\backslash$$\backslash$newline (1 to 2) \\
3 & 2 & 3 & 4 & 2 $\backslash$$\backslash$newline (3 to 4) \\
\hline
\end{tabular}
\end{table}
接下来我看着xtable
help和graph gallery,我想我也许能使用sanitise.text.function
明确指定替代\
与\
(我可以那么就使用\newline
我paste0()
调用中),但不幸的是,这并不工作,要么作为第二\
被视为逃避跟随着摹关闭双引号...
xtable(my.data, sanitise.text.function = function(str)gsub("\", "\",str,fixed=TRUE))
Error: unexpected input in:
"xtable(my.data,
sanitise.text.function = function(str)gsub("\", "\"
我可以用整个字符串\newline
和自身代替它?
my.data$out <- paste0(my.data$V1,
" \newline (",
my.data$V2,
" to ",
my.data$V3,
")")
xtable(my.data, sanitise.text.function = function(str)gsub("\newline", "\newline",str,fixed=TRUE))
% latex table generated in R 3.2.0 by xtable 1.7-4 package
% Wed Jun 24 12:05:25 2015
\begin{table}[ht]
\centering
\begin{tabular}{rllll}
\hline
& V1 & V2 & V3 & out \\
\hline
1 & 1 & 0 & 2 & 1
ewline (0 to 2) \\
2 & 2 & 1 & 3 & 2
ewline (1 to 3) \\
3 & 3 & 2 & 4 & 3
ewline (2 to 4) \\
\hline
\end{tabular}
\end{table}
因为\n
没有快乐过xtable
解析时,现在被视为断行。
This thread使用identity
作为函数参数sanitise.text.function
建议,但没有工作,要么(也没有使用function(x){x}
身份功能)。我发现一个post on R-help问相似(但问题是与\t
被解释为一个选项卡),但也没有工作(为简洁起见,再次输出省略)。
my.data
V1 V2 V3 out
1 1 0 2 1 \\newline (0 to 2)
2 2 1 3 2 \\newline (1 to 3)
3 3 2 4 3 \\newline (2 to 4)
xtable(my.data, sanitise.text.function = identity)
% latex table generated in R 3.2.0 by xtable 1.7-4 package
% Wed Jun 24 13:09:47 2015
\begin{table}[ht]
\centering
\begin{tabular}{rllll}
\hline
& V1 & V2 & V3 & out \\
\hline
1 & 1 & 0 & 2 & 1 $\backslash$newline (0 to 2) \\
2 & 2 & 1 & 3 & 2 $\backslash$newline (1 to 3) \\
3 & 3 & 2 & 4 & 3 $\backslash$newline (2 to 4) \\
\hline
\end{tabular}
\end{table}
my.data
V1 V2 V3 out
1 1 0 2 1 \newline (0 to 2)
2 2 1 3 2 \newline (1 to 3)
3 3 2 4 3 \newline (2 to 4)
xtable(my.data,
sanitise.text.function = identity)
% latex table generated in R 3.2.0 by xtable 1.7-4 package
% Wed Jun 24 13:28:28 2015
\begin{table}[ht]
\centering
\begin{tabular}{rllll}
\hline
& V1 & V2 & V3 & out \\
\hline
1 & 1 & 0 & 2 & 1
ewline (0 to 2) \\
2 & 2 & 1 & 3 & 2
ewline (1 to 3) \\
3 & 3 & 2 & 4 & 3
ewline (2 to 4) \\
\hline
\end{tabular}
\end{table}
这感觉就像我接近使用sanitise.text.function
选择,但我不能工作了。有没有办法做到这一点?
在此先感谢您的任何建议/见解。
感谢您的建议,我在完成这项工作的截止日期的最后一周,我忙于检查,但一旦工作完成,我会整理一些东西。 – slackline