我的访问表如下:Oracle。如何输出日期和时间?
insert into Visit
values(12, to_date('19-JUN-13', 'dd-mon-yy'), to_date('19-JUN-13 12:00 A.M.' , 'dd-mon-yy hh:mi A.M.'));
insert into Visit
values(15, to_date('20-JUN-13', 'dd-mon-yy'), to_date('20-JUN-13 02:00 A.M.' , 'dd-mon-yy hh:mi A.M.'));
insert into Visit
values(18, to_date('21-JUN-13', 'dd-mon-yy'), to_date('21-JUN-13 10:30 A.M.' , 'dd-mon-yy hh:mi A.M.'));
当我尝试进行查询: select * from Visit
我得到:
SQL> select * from visit;
SLOTNUM DATEVISIT ACTUALARRIVALTIME
---------- --------- ------------------------------
12 19-JUN-13 19-JUN-13
15 20-JUN-13 20-JUN-13
18 21-JUN-13 21-JUN-13
SQL> spool off;
怎么来的时候是不是有?
是否应该是HH:MI:SS而不是HH:M:SS? –
正确@MaximEliseev,谢谢你让我知道!这是一个错字。我已经用您的修复程序更新了答案。 –