我的代码:json_encode JSON.parse意外标记<
function callback(request, prim_key) {
var type = request.getResponseHeader("Content-Type");
if (type === "application/json") {
console.log(request.responseText);
var response = JSON.parse(request.responseText);
if (!response['success']) {
alert("Error!\n\nError number: " + response['errno'] + "\n\nError string: " + response['error']);
}
else {
alert("Update Successful!");
}
var els = getElementsByClass(prim_key);
for (var i = 0; i < els.length; i++) {
if (els[i].type != 'checkbox') {
els[i].innerHTML = response[els[i].headers];
}
}
} else {
alert("not a json reponse! check database for errors.");
}
}
当我打电话jason.parser,并给我下面的错误消息,它将停止:
Uncaught SyntaxError: Unexpected token < .
我尽力劝慰请求.responseText,并得到如下结果: update:实际上,我意识到request.responseText不仅包含我想要的数据,还包含了开头的html文件,我认为这是我的问题,但我不知道如何解决它。
{"success":true,"ID":"131","Manufacturing_ID":"88888","Sequence_Name":"NDU","Bases":"22","Sequence":"TGG AGA TGT GTG CGT TCT TCTGG AGA TGT GTG CGT TCT TCTGG AGA TGT GTG CGT TCT TC","Tm_C":"55.00000000","nmoles":"26.0","Owner":"Liang","Species":"gallus"}
似乎没有“<”在我的“resonseText'.any的想法,感谢
更新:其实,我知道request.responseText不只是包含下面我想要的数据,而且还含有在开始的HTML文件,我认为这是我的问题,但我不知道如何解决它。
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"...................
{"success":true,"ID":"131","Manufacturing_ID":"88888","Sequence_Name":"NDU","Bases":"22","Sequence":"TGG AGA TGT GTG CGT TCT TCTGG AGA TGT GTG CGT TCT TCTGG AGA TGT GTG CGT TCT TC","Tm_C":"55.00000000","nmoles":"26.0","Owner":"Liang","Species":"gallus"}
my php code:
$query = "SELECT * FROM $table WHERE ";
$i = 0;
foreach ($pks as $pk) {
$query .= "$pk='$pvs[$i]' AND ";
$i++;
}
$query = rtrim($query, " AND ");
$result = $db_conn->query($query);
$row = $result->fetch_assoc();
//$flag_key='';
if ($db_conn->errno) {
echo "oops";
} else {
foreach ($row as $key => $value) {
$response[$key] = $value;
//$flag_key .=$key.'-'.$value.'***';
}
}
header('Content-Type: application/json');
echo json_encode($response);
发布JSON,但很可能它是一个javscript对象。您可以使用Chrome或Firefox的控制台来设置断点并查看JSON的情况。 – abc123
对于abc123的评论,你确定你还没有发回HTML吗?如果它不能解析第一个字符 - 这将是HTML响应中的一个“<”,这将是有意义的。 (相当于在ASP.NET中发送PartialView或类似内容) – JasCav
当您说“得到下面的结果:”我想你忘了复制结果,所以我们不知道它是什么。 –