在C++中检查stoi（）函数中的int限制

Question

我给出了一个字符串y，我保证它只包含数字。在使用stoi函数将其存储在int变量中之前，如何检查它是否超出整数的范围？

string y = "2323298347293874928374927392374924" 
int x = stoi(y); // The program gets aborted when I execute this as it exceeds the bounds 
       // of int. How do I check the bounds before I store it? 

Answer 1

您可以使用异常处理机制：

#include <stdexcept> 

std::string y = "2323298347293874928374927392374924" 
int x; 

try { 
    x = stoi(y); 
} 
catch(std::invalid_argument& e){ 
    // if no conversion could be performed 
} 
catch(std::out_of_range& e){ 
    // if the converted value would fall out of the range of the result type 
    // or if the underlying function (std::strtol or std::strtoull) sets errno 
    // to ERANGE. 
} 
catch(...) { 
    // everything else 
} 

detailed description of stoi function and how to handle errors

Answer 2

捕捉到了异常：

string y = "2323298347293874928374927392374924" 
int x; 

try { 
    x = stoi(y); 
} 
catch(...) { 
    // String could not be read properly as an int. 
} 

Answer 3

如果该字符串表示的值，这是一个合法的可能性太大以至于无法存储在int中，请将其转换到更大的东西，并检查结果是否符合int：

long long temp = stoll(y); 
if (std::numeric_limits<int>::max() < temp 
    || temp < std::numeric_limits<int>::min()) 
    throw my_invalid_input_exception(); 
int i = temp; // "helpful" compilers will warn here; ignore them.