挽救了两个图可以superposed_ Matlab的

Question

我挽救了两个MATLAB数字为PNG，我希望他们有相同的大小，以是完全叠加的。

第一个数字是由函数“FilledCircle2”，这是分成两半以两种颜色的圆计算。 第二个图是由函数“FilledCircleL”，这是由函数“FilledCircle2”计算出的圆的左半部分进行计算。

我希望能有两个数字，都具有相同的尺寸，使他们能够完全重合。 有人可以帮助我理解我在做什么错？

这是我的代码时，以两者的功能和相应的输出：

function []=FilledCircle2(x0,y0,Radius,N, col1, col2) 
if(N<=1) 
    error('N must be greater than 1'); 
end 
hold on 
axis equal 
axis off 
hold on 

t=(0:N)*2*pi/N; %t=-pi:0.01:pi 
x=Radius*cos(t)+x0; 
y=Radius*sin(t)+y0; 
plot(x,y) 
hold on 

%Divide circle in to 2 equal parts 
n=2; 
thetas = linspace(-pi, pi,n+1); %linspace generates n points. The space between the points is [(pi/2)-(-pi/2)]/(n) 

% Specify any colors wanted 
colors = [col1; col2]; 

for k = 1:n 
    tt = linspace(thetas(k), thetas(k+1)); 
    xi = Radius * cos(tt) + x0; 
    yi = Radius * sin(tt) + y0; 
    c2= fill([xi(:); x0], [yi(:); y0], colors(k,:)); %Assign diffrent colors to each circle 'slice' 

    set (c2, 'edgecolor','white') 
    set(c2,'LineWidth',2.0) 

    set(gcf,'PaperUnits','inches','PaperSize',[0.8666,0.8666],'PaperPosition',[0 0 0.8666 0.8666])%setting size (130/150, 130/150, 150pixels per inch being the default size of img), paper position is imporrtant as otherwise i will have extra border 
    set(gca, 'Position', [0 0 1 1]); 
    set(gcf,'color',[0.49019607843137 0.49019607843137 0.49019607843137])%figure properties, rgb(125/255,125/255,125/255) 
    fig = gcf; 
    fig.InvertHardcopy = 'off'; %saves the fig with the set background color 

    %rotates the plot 
    az= 90; %azimuth, az, is the horizontal rotation about the z axis as measured in degrees from the negative y-axis. Positive values indicate counterclockwise rotation 
    el= 90; % vertical elevation of the view point in degrees 
    view(az,el); 
    hold on 
end 

这里是功能FilledCircle2(0,0,10,300, 'y', 'r')的输出：

[

function []=HalfFilledCircleL(x0,y0,Radius,N, col1) 

if(N<=1) 
    error('N must be greater than 1'); 
end 

hold on 
axis equal 
% axis tight 
axis off 
hold on 

t=(0:N)*(-pi)/N; %t=-pi:0.01:pi 
x=Radius*cos(t)+x0; 
y=Radius*sin(t)+y0; 


hold on 

c1=fill(x,y,col1); %filling the semi-circle 
set (c1, 'edgecolor','white') %setting the outline color of the semi-circle 
set(gcf,'color',[0.49019607843137 0.49019607843137 0.49019607843137])%figure properties, rgb(125/255,125/255,125/255) 
set(c1,'LineWidth',2.0) 
set(gcf,'PaperUnits','inches','PaperSize',[0.8666,0.8666],'PaperPosition',[0 0 0.8666,0.8666])%setting size (130/150, 130/150, 150pixels per inch being the default size of img), paper position is imporrtant as otherwise i will have extra border 
set(gca, 'Position', [0 0 1 1]); 
fig = gcf; 
fig.InvertHardcopy = 'off'; %saves the fig with the set background color 


% %rotates the plot 
az= 90; %azimuth, az, is the horizontal rotation about the z axis as measured in degrees from the negative y-axis. Positive values indicate counterclockwise rotation 
el= 90; % vertical elevation of the view point in degrees 
view(az,el); 

end 

这里是该函数的输出HalfFilledCircleL(0,0,10,300, 'r')：

Answer 1

使用xlim和ylim设置轴的XY限制：

figure; 
HalfFilledCircleL(0,0,10,300, 'r'); 
xlim([-12 12]);ylim([-12 12]); 
az= -90; %azimuth, az, is the horizontal rotation about the z axis as measured in degrees from the negative y-axis. Positive values indicate counterclockwise rotation 
el= 90; % vertical elevation of the view point in degrees 
view(az,el); 

figure; 
FilledCircle2(0,0,10,300, 'y', 'r'); 
xlim([-12 12]);ylim([-12 12]);