C++ do/while循环和调用函数？

Question

我很难试图让这个程序循环，如果用户输入'y'他们想继续。我是非常新的编程方式，所以任何帮助非常感谢。我认为最好的做法是在main中添加一个do/while，如果他们想要在代码的最后继续添加用户，但我很快意识到，除非我调用用于用户输入的以前方法并输出。这就是问题出现的地方。

再次感谢您的帮助！

/* 

• Ask the user if they want to enter the data again (y/n). 
• If ’n’, then the program ends, otherwise it should clear the student class object and 
repeat the loop (ask the user to enter new data...). 

*/ 
#include <iostream> 
#include <cstdlib> 
#include <string> 

using namespace std; 

class Student { 
    public: 
    Student(); 
    ~Student(); 
    void InputData();  // Input all data from user 
    void OutputData();  // Output class list to console 
    void ResetClasses();  // Reset class list 
    Student& operator =(const Student& rightSide); // Assignment operator 

private: 
    string name; 
    int numClasses; 
    string *classList; 
}; 


//array intialized to NULL 
Student::Student() { 
    numClasses = 0; 
    classList = NULL; 
    name = ""; 
} 

//Frees up any memory of array 
Student::~Student() { 

if(classList != NULL) { 
    delete [] classList; 
} 
} 

// This method deletes the class list 
// ====================== 
void Student::ResetClasses() { 
    if(classList != NULL) { 
     delete [ ] classList; 
     classList = NULL; 
} 
numClasses = 0; 
} 



//inputs all data from user (i.e. number of classes) 
//using an array to store classes 
void Student::InputData() { 
int i; 

// Resets the class list in case the method 
// was called again and array wasn't cleared 
ResetClasses(); 

cout << "Enter student name." << endl; 
getline(cin, name); 
cout << "Enter number of classes." << endl; 
cin >> numClasses; 
cin.ignore(2,'\n'); // Discard extra newline 
if (numClasses > 0) { 
    //array to hold number of classes 
    classList = new string[numClasses]; 
    // Loops through # of classes, inputting name of each into array 
    for (i=0; i<numClasses; i++) { 
     cout << "Enter name of class " << (i+1) << endl; 
     getline(cin, classList[i]); 
    } 
} 
cout << endl; 
} 

// This method outputs the data entered by the user. 
void Student::OutputData() { 

int i; 
cout << "Name: " << name << endl; 
cout << "Number of classes: " << numClasses << endl; 
for (i=0; i<numClasses; i++) { 
    cout << " Class " << (i+1) << ":" << classList[i] << endl; 
} 
cout << endl; 
} 


/*This method copies a new classlist to target of assignment. If the operator isn't overloaded  there would be two references to the same class list.*/ 
Student& Student::operator =(const Student& rightSide) { 

int i; 
// Erases the list of classes 
ResetClasses(); 
name = rightSide.name; 
numClasses = rightSide.numClasses; 

// Copies the list of classes 
if (numClasses > 0) { 
    classList = new string[numClasses]; 
    for (i=0; i<numClasses; i++) { 
     classList[i] = rightSide.classList[i]; 
    } 
} 
return *this; 
} 

//main function 
int main() { 
    char choice; 
do { 
// Test our code with two student classes 
Student s1, s2; 

s1.InputData();  // Input data for student 1 
cout << "Student 1's data:" << endl; 
s1.OutputData();  // Output data for student 1 

cout << endl; 

s2 = s1; 
cout << "Student 2's data after assignment from student 1:" << endl; 
s2.OutputData();  // Should output same data as for student 1 

s1.ResetClasses(); 
cout << "Student 1's data after reset:" << endl; 
s1.OutputData();  // Should have no classes 

cout << "Student 2's data, should still have original classes:" << endl; 
s2.OutputData();  // Should still have original classes 

cout << endl; 
cout << "Would you like to continue? y/n" << endl; 
cin >> choice; 
if(choice == 'y') { 

    void InputData();  // Input all data from user 
    void OutputData();  // Output class list to console 
    void ResetClasses();  // Reset class list 
} 
} while(choice == 'y'); 

return 0; 
} 

Answer 1

刚刚摆脱的

if(choice == 'y') { 

    void InputData();  // Input all data from user 
    void OutputData();  // Output class list to console 
    void ResetClasses();  // Reset class list 
} 

因为变量s1和s2是内部的，而DO循环，他们会在每次迭代重建。 （构造函数将在定义处被调用，析构函数将在循环的大括号处被调用，然后再测试choice == 'y'并重复）。

您遇到的另一个问题是您的标准输入不处于与再次调用s1.InputData()兼容的状态。由于您只是使用提取操作符>>来读取choice，所以解析停止在第一个空白处，并且缓冲区中至少存在（至少）一个换行符。当Student::InputData调用getline时，它会发现该换行符仍在缓冲区中，而不是等待其他输入。

这与您在阅读numClasses后使用cin.ignore的原因相同。你会想在这里做同样的事情。