我有一个JS脚本,即时通讯的代码转换到PHP,但我坚持的正确语法是创建与此相同的代码在JS在我的PHP脚本是什么:设置PHP语法一个变量
var sdata = {
"13":{
"22":["618","22","1","1","0","0","0"],
"21":["617","22","1","1","0","0","0"]
},
"14":{
"22":["619","22","1","1","0","0","0"],
"20":["622","22","1","1","0","0","0"]
},
"15":{
"20":["623","22","1","1","0","0","0"]
}
};
有什么想法?
如果你想在同一对象转换在PHP然后使用http://www.php。 net/manual/en/function.json-decode.php,否则请参阅mata的答案。 –
包装是一个对象,第一个层次也是对象,他们的子元素是数组。你想要完全相同的结构,还是只想让数据层保持一致? –
@tpaksu我想它像马塔回答:)我不解析变量的结果 - 我正在重写整个脚本:) – Sir