php-mysql投票系统？

我正在使用以下脚本在我的网站中构建一个php-mysql投票系统（如youtube中的一个）。我也使用ajax在newtest.php中执行php。我测试了自己的PHP，它工作得很好。现在我使用鼠标点击ajax投票上或下，但它不起作用。你能告诉我我要去哪里吗？（我是ajax的初学者）。此外，我想返回并显示当前投票号码自动更新。php-mysql投票系统？

$contentVar = $_POST['contentVar']; 
if ($contentVar == "con1") { 
    $db_host = "host"; 
    $db_username = "username"; 
    $db_pass = "pass"; 
    $db_name = "phphitscounter"; 

    @mysql_connect ("$db_host","$db_username","$db_pass") or die ("Could Not Connect To The Database"); 
    @mysql_select_db ("$db_name") or die ("No Database"); 
    mysql_select_db("phphitscounter", @mysql_connect ("$db_host","$db_username","$db_pass")); 

    $ip = $_SERVER['REMOTE_ADDR']; 
    $Page = $_SERVER['PHP_SELF']; 
    $pagenum = preg_replace("/[^0-9]/", '', $Page); 

    $query = mysql_query("SELECT ip FROM vote WHERE ip = '$ip' AND page = '$pagenum'"); 
    if (mysql_num_rows($query) > 0) { 
     echo "You have already voted"; 
    } 
    else{ 
     echo "Thank you for voring"; 
     mysql_query("INSERT INTO vote (ip, page, voteup, votedown) VALUES ('$ip', '$pagenum', 0, 0)"); 
     mysql_query("UPDATE vote SET voteup = voteup + 1 WHERE ip = '$ip' AND page = '$pagenum'"); 
    } 

    $voteup = mysql_query("SELECT voteup FROM vote WHERE ip = '$ip' AND page = '$pagenum'"); 
    $results_voteup = mysql_fetch_array($voteup, MYSQL_NUM); 
    print ($results_voteup[0]); 
    echo "1"; 
} 
else if ($contentVar == "con2") { 
    $db_host = "host"; 
    $db_username = "username"; 
    $db_pass = "pass"; 
    $db_name = "phphitscounter"; 

    @mysql_connect ("$db_host","$db_username","$db_pass") or die ("Could Not Connect To The Database"); 
    @mysql_select_db ("$db_name") or die ("No Database"); 
    mysql_select_db("phphitscounter", @mysql_connect ("$db_host","$db_username","$db_pass")); 

    $ip = $_SERVER['REMOTE_ADDR']; 
    $Page = $_SERVER['PHP_SELF']; 
    $pagenum = preg_replace("/[^0-9]/", '', $Page); 

    $query = mysql_query("SELECT ip FROM vote WHERE ip = '$ip' AND page = '$pagenum'"); 
    if (mysql_num_rows($query) > 0) { 
     echo "You have already voted"; 
    } 
    else { 
     echo "Thank you for voring"; 
     mysql_query("INSERT INTO vote (ip, page, voteup, votedown) VALUES ('$ip', '$pagenum', 0, 0)"); 
     mysql_query("UPDATE vote SET votedown = votedown + 1 WHERE ip = '$ip' AND page = '$pagenum'"); 
    } 

    $votedown = mysql_query("SELECT voteup FROM vote WHERE ip = '$ip' AND page = '$pagenum'"); 
    $results_votedown = mysql_fetch_array($votedown, MYSQL_NUM); 
    print ($results_votedown[0]); 
    echo "2"; 
}

的test.php的页面：

<html> 

<head> 
    <script type="text/javascript" src="Scripts/jquery.js"></script> 
    <script language="JavaScript" type="text/javascript"> 
    function swapContent(cv) { 
     $("#myDiv").html('<img src="Assets/loading.gif" width="50" height="50"/>').show(); 
     var url = "scripts/newtest.php"; 
     $.post(url, { 
      contentVar: cv 
     }, function(data) { 
      $("#myDiv").html(data).show(); 
     }); 
    } 
    </script> 
    <style type="text/css"> 
    #myDiv { 
     width: 200px; 
     height: 150px; 
     padding: 12px; 
     border: #666 1px solid; 
     background-color: #FAEEC5; 
     font-size: 18px; 
    } 
    </style> 
</head> 

<body> 
    <img src="Assets/like.png" href="#" onClick="return false" onmousedown="javascript:swapContent('con1');" /> 
    <img src="Assets/dislike.png" href="#" onClick="return false" onmousedown="javascript:swapContent('con2');" /> 
    <div id="myDiv"></div> 
</body> 

</html>

来源

2012-04-06 user1200640

替换此代码：

<img src="Assets/like.png" href="#" onClick="return false" onmousedown="javascript:swapContent('con1');"/> 
<img src="Assets/dislike.png" href="#" onClick="return false" onmousedown="javascript:swapContent('con2');"/>

有了：

<img src="Assets/like.png" href="#" id="up"/> 
<img src="Assets/dislike.png" href="#"id="down"/> 

<script> 
$('#up').mousedown(function() { 
swapContent('con1'); 
}); 

$('#down').mousedown(function() { 
    swapContent('con2'); 
}); 
</script>

来源

2012-04-06 06:39:02 elo

做这样的事情

<img src="Assets/like.png" href="#" onClick="swapContent(1);"/> 
<img src="Assets/dislike.png" href="#" onClick="swapContent(2);"/> 

function swapContent(value){ 

$("#myDiv").html('<img src="Assets/loading.gif" width="50" height="50"/>').show(); 
var url = "scripts/newtest.php"; 
$.post(url, {contentVar: value} ,function(data) { 
    $("#myDiv").html(data).show(); 
}); 


}

来源

2012-04-06 06:47:27

php-mysql投票系统？

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